[ashishjha100]

Originally Posted by *arch*

Another one from GMAT Prep:-

If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?

1) On the number line, z is closer to 10 than it is to x.
2) z = 5x

My pick is A.

1. Mean will be midway b/w x & 10. it says that z closer to 10....that means z greater than mean.

2.No particular information helpful to solve the problem......

[mockingabird]

Originally Posted by ashishjha100

x>y
x=1
y=-5

mockingabird,
ur given example is not valid.......it does not give x/y>1

Yup overlooked it
Ans is C

Here is how it works
look at the two statements we infer that
both of them are positive or both of them are negative
and that x>y

Taking into consideration all these 3:
x- y = 1/2
-2+5/2 =1/2
but
x/y = 4/5 which violates that x/y>1

so they have to be both positive!!

[mockingabird]

Originally Posted by *arch*

Another one from GMAT Prep:-

If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10?

1) On the number line, z is closer to 10 than it is to x.
2) z = 5x

Ans is A

The closest you can get is x=7 z=9
17/2=8.5 <9

The farthest range is x=1 z=9
11/2=5.5<9

consistent in the entire range.


The second one:
x=1
11/2= 5.5 5*x= 5
5.5>5

x=2
12/2=6 2*5=10

6<10

inconsistent

[karedia.a]

which two equation do we have
a+b= -1 and ab= -6 so how can we find a and b from this

[alchemist-mba]

Originally Posted by karedia.a

which two equation do we have
a+b= -1 and ab= -6 so how can we find a and b from this

you need both of these equations to find a and b.

[Simmy]

In the xy-plane, what is the slope of line l?
(1) Line l dose not intersect the line with equation y = 1 - x.
(2) Line l intersects the line with equation y = x – 1.


What is the value of the integer k?
(1) k + 3 > 0
(2) k^4 <= 0


If x and y are positive, is x^3 > y?
(1) √x > y
(2) x > y

[alchemist-mba]

Originally Posted by Simmy

In the xy-plane, what is the slope of line l?
(1) Line l dose not intersect the line with equation y = 1 - x.
(2) Line l intersects the line with equation y = x – 1.


What is the value of the integer k?
(1) k + 3 > 0
(2) k^4 <= 0

If x and y are positive, is x^3 > y?
(1) √x > y
(2) x > y

My take - A,B,D

1. stmt 1 - Line 'l' doesnt intersect y=1-x.. => the line l must be parallel to
y=1-x.. and hence line l's slope must be equal to line y=1-x's slope... ->
sufficient.
stmt 2 - Line 'l' intersects y=x-1. It can intersect at any angle...so slope cant be decided...

2. stmt 1 - K =3 >0 => k can be -2, -1, 0, 1,2,3,,........ not sufficeint
stmt 2 - K^4 < = 0.. for integer values... power 4 can never be less than zero.. hence K ^ 4 = 0.. whihc leave only one integer value '0' -- sufficient

3. both x & y are positive

stmt 1: √x > y => x > y^2 => x^3 > Y^6,
and since ^6 > y => x^3 > y -- -sufficient
stmt 2: x > y => x^3 > y ^3...and since y^3 < y => x^3 > y - sufficient

[Simmy]

Originally Posted by alchemist-mba

My take - A,B,D

OA's are A, B, E

[Simmy]

Originally Posted by alchemist-mba

My take - A,B,D

1. stmt 1 - Line 'l' doesnt intersect y=1-x.. => the line l must be parallel to
y=1-x.. and hence line l's slope must be equal to line y=1-x's slope... ->
sufficient.
stmt 2 - Line 'l' doesnt intersect y=x-1. It can intersect at any
angle...so slope cant be decided...

3. both x & y are positive

stmt 1: √x > y => x > y^2 => x^3 > Y^6,
and since ^6 > y => x^3 > y -- -sufficient
stmt 2: x > y => x^3 > y ^3...and since y^3 < y => x^3 > y - sufficient

Hi Alchemist,

Two queries:
1) In statement 2 question number 1, you have mentioned line L doesn't intersect y=x-1; However in actual question the statement 2 says

(2) Line l intersects the line with equation y = x – 1.


2) Question 3 - statement 1 says √x > y ;
Here it can be 1/2 > 1/4
so x^3>y; (1/4)^3 >1/4; 1/64 < 1/4 so x^3<y
If √x > y => 2>1;
so x^3>y; (4)^3 >1; 64> 2 so x^3>y
Not sufficient

[alchemist-mba]

Originally Posted by Simmy

Hi Alchemist,

Two queries:
1) In statement 2 question number 1, you have mentioned line L doesn't intersect y=x-1; However in actual question the statement 2 says

(2) Line l intersects the line with equation y = x – 1.


2) Question 3 - statement 1 says √x > y ;
Here it can be 1/2 > 1/4
so x^3>y; (1/4)^3 >1/4; 1/64 < 1/4 so x^3<y
If √x > y => 2>1;
so x^3>y; (4)^3 >1; 64> 2 so x^3>y
Not sufficient

2. line 2 - it was a copy paste .... sorry.. but the explanation is correct..

3. Yep i missed the decimal part.. and thought them to be integers.....and yes..it is E.