[carobee]

Originally Posted by maverick.jd

If y is greater than 110 percent of x,is y greater than 75
1.x>75
2.y-x=10

given y>1.1x.

taking condition 1) x>75 will always give y>1.1 *75. hence y>75

now take condition 2) y-x=10=>x=y-10.
y>1.1(y-10)=>y>1.1y -11=>0.1y<11=>y<110.
hence we can't say if y>75
so only statement 1) gives the answer

[radhika5481]

Hi All,

A couple of questions encoutered in practice tests:

1. Is 1/p > r/(r*r + 2)

a. p=r
b. r > 0


-----------------------

2. If m and n are integers, is m odd.

a. n+m is odd
b. n+m = n*n + 5

----------------------------------------

3. If y > = 0, what is the value of x.

a. |x - 3| > = y
b. |x - 3| = < - y

I have the answers, but need help with reasoning.
Hence please post the approach and reasoning as well.

Thanks in advance.

[Rockeeze]

hi radhika
for the first two DS ques

1. both the statements are req.
2. only b is sufficient

do tell the ans, if correct i ll post the soln.

regards
rock

[radhika5481]

Originally Posted by Rockeeze

hi radhika
for the first two DS ques

1. both the statements are req.
2. only b is sufficient

do tell the ans, if correct i ll post the soln.

regards
rock

Both are correct.

[pops80]

2. If m and n are integers, is m odd.

a. n+m is odd
b. n+m = n*n + 5

B is sufficient

if n is odd, then n*n is odd and n*n+5 is even. Thus only an odd number (m) when added to n will produce an even number
if n is even, then n*n is even and n*n+5 is odd. Thus only an odd number (m) when added to n will produce an odd number

n+m is odd - is leaving the options open because one of them could be odd and still meet the condition


3. If y > = 0, what is the value of x.

a. |x - 3| > = y
b. |x - 3| = < - y

I believe again b will be sufficient to answer the question (though i am not sure) because the only condition that will satisfy the condition b is abs(x-3)=0 otherwise x = 3 ... i will wait for other readers to reply to that question

thanks

[Rockeeze]

1. Is 1/p > r/(r*r + 2)

1. p=r
2. r > 0

from stat.1 we have a number of options
as p and q can be positive, negative as well as fractions
so nuthing cn be definite
now using stat.2 alone which specifies r>0
we surely cant reach any conclusion

but definitly using both 1& 2
we reach a common ans regardless
of the fact if dey r in decimal form or integers.

2. If m and n are integers, is m odd.

1. n+m is odd
2. n+m = n*n + 5

here using stat. 1 we cnt concluted about m as it cn be both
even or odd depending upon n
now, we move on to stat.2
we cn rearrange the condition as
n^2-n+(5-m)=0
simply try n substitute once and even value and den an odd value for n
i.e
if n=2 den m=7
if n=3 den m= 11
observing the pattern for a few mr nos
we cn definetly say for either n being even or odd
m has to be odd

hope it helps

regards
rock

[carobee]

Originally Posted by radhika5481

Hi All,

A couple of questions encoutered in practice tests:

1. Is 1/p > r/(r*r + 2)

a. p=r
b. r > 0


-----------------------

2. If m and n are integers, is m odd.

a. n+m is odd
b. n+m = n*n + 5

----------------------------------------

3. If y > = 0, what is the value of x.

a. |x - 3| > = y
b. |x - 3| = < - y

I have the answers, but need help with reasoning.
Hence please post the approach and reasoning as well.

Thanks in advance.

1) 1/p>r/(r*r +2)
=>r*r +2>pr
=>r*r -pr +2>0 -----eqn
condition a)if p=r then
eqn => 2>0.
hence condition a) is sufficient to answer the question

2)
a) m+n =odd, hence either m=odd and n=even or else m=even and n=odd
d)n+m=n*n +5
=>n*n -n=m-5
=>n(n-1)=m-5
consider n=even then n-1=odd, so n(n-1)=even. assuming m=odd,if m=7,9... etc then m-5=even
hence both the condition are required.

3)given y>=0
a)|x - 3| > = y
=>|x - 3| > =0
=>x-3>=0
=>x>=3
b)|x - 3| = < - y
=>|x - 3| =< 0
=>-x +3=<0
=>x>=3
hence anyone of the condition will give the range but not accurate value

[radhika5481]

Originally Posted by pops80

2. If m and n are integers, is m odd.

a. n+m is odd
b. n+m = n*n + 5

B is sufficient

if n is odd, then n*n is odd and n*n+5 is even. Thus only an odd number (m) when added to n will produce an even number
if n is even, then n*n is even and n*n+5 is odd. Thus only an odd number (m) when added to n will produce an odd number

n+m is odd - is leaving the options open because one of them could be odd and still meet the condition


3. If y > = 0, what is the value of x.

a. |x - 3| > = y
b. |x - 3| = < - y

I believe again b will be sufficient to answer the question (though i am not sure) because the only condition that will satisfy the condition b is abs(x-3)=0 otherwise x = 3 ... i will wait for other readers to reply to that question

thanks

Yes. You are right with both answers. thanks for the explanation.

[nidhisoni24]

Is u>v ?
1) u^2=v^2
2) u,v>0
A) Statement 1 alone is sufficient but statement 2 alone is not sufficient to answer the question asked.
B) Statement 2 alone is sufficient but statement 1 alone is not sufficient to answer the question asked.
C) Both statements 1 and 2 together are sufficient to answer the question but neither statement is sufficient alone.
D) Each statement alone is sufficient to answer the question.
E) Statements 1 and 2 are not sufficient to answer the question asked and additional data is needed to answer the statements.

i think answer cant be determined

[carobee]

Originally Posted by nidhisoni24

Is u>v ?
1) u^2=v^2
2) u,v>0
A) Statement 1 alone is sufficient but statement 2 alone is not sufficient to answer the question asked.
B) Statement 2 alone is sufficient but statement 1 alone is not sufficient to answer the question asked.
C) Both statements 1 and 2 together are sufficient to answer the question but neither statement is sufficient alone.
D) Each statement alone is sufficient to answer the question.
E) Statements 1 and 2 are not sufficient to answer the question asked and additional data is needed to answer the statements.

i think answer cant be determined

i guess the answer sud be C)