[Darth Maul]

Please solve the following

In a group of 6 people, the average (arithmetic mean) height of any two people in the group is less than 175 cm. How many people in the group have a height of 175 cm or greater?

(1) There is one person in the group who is 180 cm tall.
(2) The average height for the entire group is below 175

[siddharthaduggirala]

Originally Posted by Darth Maul

Will go with C

1) x can be fractions ...not suff
2) x^2 = set of all integers .... not suff

1 & 2 )

x can be 2 or 3

when x = 2
y = 9

when x = 3
y = 8

combining 1 & 2 is sufficient

I think you missed on the condition where x=1.414 and x^2=2. the same for
x^2=3.

So the ans must be E.

[siddharthaduggirala]

Originally Posted by Darth Maul

Please solve the following

In a group of 6 people, the average (arithmetic mean) height of any two people in the group is less than 175 cm. How many people in the group have a height of 175 cm or greater?

(1) There is one person in the group who is 180 cm tall.
(2) The average height for the entire group is below 175

IMO A.

from the info in the ques we know that avg height of any two individuals is <175.

so from 1) we know that there is only 1 person in the group with height of 180. if there is one more person with a height > 175 then the avg will be > 175. so 1) alone is suff.

Now 2) we know that total sum of heights is <175*6.

but we dont know whether we have a single person with a height above 175 or no person with a height above 175.

Hence insuff.

Please post the OA?

[friend9921]

Originally Posted by amsey1382

Q2:
If 2 different representatives are to be selected at random from a group of 10 employees and if p is the probability that both representatives selected will be women, is p > 1/2 ?
(1) More than half of the 10 employees are women.
(2) The probability that both representatives selected will be men is less than 1/10

Although the problem was posted just 10 days back, I could not find the OA and my answer did not match with the answers arrived at by fellow puys.

My method goes like this.

Statement 1: (Not sufficient)
We can have 6, 7, 8, 9 women

6C2 / 10C2 = 0.33
However, 9C2 / 10C2 = 0.8

Since we get both the answers as 0.33<0.5<0.8, the statement becomes insufficient.

Statement 2: Sufficient

As the statement says that probability of both rep are men is less than 1/10. We can thus safely arrive that probability of both rep women is more than 1/2.

1/10 means less than 10%.

Thus for the probability of both rep women could be 90%, 91%, 92%, 93%..... which is more than 50%...

Dunno if i have overlooked something...

[deepakraam]

Originally Posted by Darth Maul

Please solve the following

In a group of 6 people, the average (arithmetic mean) height of any two people in the group is less than 175 cm. How many people in the group have a height of 175 cm or greater?

(1) There is one person in the group who is 180 cm tall.
(2) The average height for the entire group is below 175

Since the avg height of ANY two persons is less than 175,atmost we can have only one person whose height is >=175.

Statement1:
=========
This statement tells that the tallest person is 180cm and this will be only one person whose height > 175.This is suff.

Statement 2:
==========
Nt suff.

[rohit_gem2611]

Originally Posted by Darth Maul

Please solve the following

In a group of 6 people, the average (arithmetic mean) height of any two people in the group is less than 175 cm. How many people in the group have a height of 175 cm or greater?

(1) There is one person in the group who is 180 cm tall.
(2) The average height for the entire group is below 175

any 2 people in the have an average height less than 175

Statement 1 --> One person with height 180
So for average height of any 2 people to be less than 175 the height of all other people should be less than 170...... bcoz (170+180)/2=175
So only 1 person in the group has height greater than 175....
Sufficient

Statement 2 --> Average height of group is less than 175 . Dosent help in finding the solution

So IMO option A
What's the OA??

[Darth Maul]

Originally Posted by Darth Maul

Please solve the following

In a group of 6 people, the average (arithmetic mean) height of any two people in the group is less than 175 cm. How many people in the group have a height of 175 cm or greater?

(1) There is one person in the group who is 180 cm tall.
(2) The average height for the entire group is below 175

all of you nailed it ... OA is A

[siddharthaduggirala]

Originally Posted by Darth Maul

all of you nailed it ... OA is A

But i felt this was a tricky question.

[sheorp]

Originally Posted by friend9921

Although the problem was posted just 10 days back, I could not find the OA and my answer did not match with the answers arrived at by fellow puys.

My method goes like this.

Statement 1: (Not sufficient)
We can have 6, 7, 8, 9 women

6C2 / 10C2 = 0.33
However, 9C2 / 10C2 = 0.8

Since we get both the answers as 0.33<0.5<0.8, the statement becomes insufficient.

Statement 2: Sufficient

As the statement says that probability of both rep are men is less than 1/10. We can thus safely arrive that probability of both rep women is more than 1/2.

1/10 means less than 10%.

Thus for the probability of both rep women could be 90%, 91%, 92%, 93%..... which is more than 50%...

Dunno if i have overlooked something...

probability of both men< 1/10 , now assuming no.of men :2, 3,4...and trying one by one
suppose M=2, prob = 1/45 which isless than 1/10
M=3, prob = 1/30 which is less than 1/10
M=4 , prob= 1/7.5 , which is greater than 1/10 hence M= 2 or 3
now if M=2 them W=8 and p= 0.62
if M=3 then W=7 and P= 0.46 hence Not sufficient
combining 1& 2 also doesn't answer .
ans : E

[nuttyvarun]

if p, s, and t are positive prime numbers, what is the value of p^3s^3t^3?
(1) p^3st=728

(2) t=13