[nuttyvarun]

Originally Posted by bhavin422

hey varun ...not necessary that x wud be -ve.
St 2 has 2 alternatives. y could be zero and x could be any real no OR x is -ve ...
So combines we cannot sat that x is necessarily negative ...

Ans E

Well I was left with only C and E to chose from.. but if u wud combine the 2 option in the question u wud see that both option give X as possibly -ve.. which kinda reinforces that X is not 0 and not +ver either.. thats' how -ve..

your thoughts..!!..

[bhavin422]

Originally Posted by amsey1382

Time to try some tough one...
IS X a negative number?

1) X^2 is a positive number
2) x. |Y| is not a positive number

Originally Posted by nuttyvarun

Well I was left with only C and E to chose from.. but if u wud combine the 2 option in the question u wud see that both option give X as possibly -ve.. which kinda reinforces that X is not 0 and not +ver either.. thats' how -ve..

your thoughts..!!..

well..

St 1 : x is +ve or -ve
St 2: x. |Y| is not a positive number implies product is 0 or -ve

possibilities:
a) X=0 and Y is any no
OR
b) x= any real no and y = 0
OR
c) x= -ve and y = any no

combined statements :

It tells us x is not zero ...so option a) of St 2 is gone ...
But still we cannot rule out option b and c of statement 2 ..

Or in other words, x can be any real no (which includes positive no) Or -ve ..still no concensus whether x is -ve ...

Hence E ..

I guess this should be correct

[nuttyvarun]

well.. for me it goes something like..

option1:
possibly X is +ve or -ve..
and
for sure X <> ZERO

option2:
possible X is zero or -ve
and
for sure X <> +ve

combining 2 we get..for sure X <> ZERO and for sure X <> +ve

thus answer can be reached with the help of both statements...

remember this is a YES/NO answer..and using the statement provided the answer can be reached, i.e. YES.

my asnwer choice still remains option C

Originally Posted by bhavin422

well..

St 1 : x is +ve or -ve
St 2: x. |Y| is not a positive number implies product is 0 or -ve

possibilities:
a) X=0 and Y is any no
OR
b) x= any real no and y = 0
OR
c) x= -ve and y = any no

combined statements :

It tells us x is not zero ...so option a) of St 2 is gone ...
But still we cannot rule out option b and c of statement 2 ..

Or in other words, x can be any real no (which includes positive no) Or -ve ..still no concensus whether x is -ve ...

Hence E ..

I guess this should be correct

[srworld]

Originally Posted by bhavin422

well..

St 1 : x is +ve or -ve
St 2: x. |Y| is not a positive number implies product is 0 or -ve

possibilities:
a) X=0 and Y is any no
OR
b) x= any real no and y = 0
OR
c) x= -ve and y = any no

combined statements :

It tells us x is not zero ...so option a) of St 2 is gone ...
But still we cannot rule out option b and c of statement 2 ..

Or in other words, x can be any real no (which includes positive no) Or -ve ..still no concensus whether x is -ve ...

Hence E ..

I guess this should be correct

Try this...

If x and y are positive, is 4x > 3y?
(1) x > y - x

(2) x/y < 1

[srworld]

Few more....
1. If x and y are positive, is 3x > 7y?

(1) x > y + 4

(2) -5x < -14y

2. If w and c are integers, is w > 0?

(1) w + c > 50

(2) c > 48

[nuttyvarun]

Yesterday Diana spent a total of 240 minutes attending a training class, responding to Emails, and talking on the phone. If she did no two of these three activities at the same time, how much time did she spend talking on the phone?

(1) Yesterday the amount of time that Diana spent attending the training class was 90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was 60 percent of the total amount of time that she spent responding to E-mails and talking on the phone.

[nuttyvarun]

What is the cube root of

w ?
(1) The 5th root of w is 64.

(2) The 15th root of w is 4.

the OA is option B.. how come..??..

[bhavin422]

Originally Posted by srworld

Try this...

If x and y are positive, is 4x > 3y?
(1) x > y - x

(2) x/y < 1

Serious connectivity issues at my end ..unable to post solutions ..

Since variables are positive, we can perform operations without worrying abt inequality
Question : Is x/y > 0.75 ?

St 1 : 2x>y i.e x/y > 0.5, so the ratio may or maynot be greater than 0.75 ..not suff ..

St 2: x/y <1 , not suff

Combined : ratio is between 0.5 and 1, it may or maynot be greater than 0.75 ...not suff ..

Ans E

[bhavin422]

Originally Posted by srworld

Few more....
1. If x and y are positive, is 3x > 7y?

(1) x > y + 4

(2) -5x < -14y

Question : Is x/y > 7/3 i.e is x/y > 2.33 ?

St 1 : mult by 3 i.e 3x> 3y +12 ..cant say if 3x is greater or not than 7y ..not suff

St 2 : mult by -ve, change in inequality, 5x>14y
i.e x/y > 14/5 ...i.e x/y > 2.8 ...suff

Ans B

[bhavin422]

Originally Posted by srworld

Few more....


2. If w and c are integers, is w > 0?

(1) w + c > 50

(2) c > 48

St 1 : no clue abt c, hence cannot predict abt w ...not suff

St 2: only tells about x, caanot say about w ...not suff

Combined : still tells us nothing , as w can be +ve or -ve
eg c=49 and w =2
Or c = 60 and w = -5 ,,

Ans E