Hi,
I have a doubt in Qn. 9 of MC1011.
The question is as follows :
Two cars P and Q start from two points A and B towards each other simultaneously. They meet for the first time 40 km from B. After meeting they exchange their speeds as well as directions and proceed to their respective starting points, they turn back with the same speeds and meet at a point 20 km from A. Find the distance between A and B.
The approach I followed was :
A------------------------------B
|---------x--------|----40km--|
The first time they meet :
time taken by P = Time Taken by Q.
Therefore, x/Vp= 40 /Vq.
The second time they meet,
Again, time taken by P = time taken by Q
Therefore, (x+20)/VQ = (40 + ( x-10))/VP
Thus, solving the above two eqns..
we get, x = 40.
Thus, answer is 80.
But, the option does not exist :(




:banghea d:
Could somebody please clarify this.