[g.iyer]

i got f(x)f(y) as 1/4

f(1)f(2)=f(2)
f(1)=1
f(1/2)f(2)=f(1)
f(1/2)=1/4

hope i m right..if not pls correct..

[vibhu_kk]

@varuniyer
f(2)f(1/2)=f(1)
f(2)f(1)=f(2), so f(1)=1
thus f(1/2)=1/4

rahim question gave me right angled triangle ABC, wer v cud solve for edges, train takes approx 4.5hrs to reach C; so rahim shud take approx 5.44hrs
still can't be sure thou

[suryas]

f(4)=f(2)*f(2)
f(4)=16

f(2)=f(4)*f(1/2)
4=16*f(1/2)
f(1/2)=1/4....

This is how i arrived at solution...puys comment please......

[vibhu_kk]

@suryas
u got it right dude....

[coolrockymehra]

i think for rahim ques it will be 6:30 cauz he has to reach dere at 12:45...n it will take him more lsighlty more den 6 houres arond 10-12 min more....so he shuld get atleast by 6:30


wat say..:smile:

[varunriyer]

how about the How many integers greater than 999 but not greater than 4000 ?

and the question on Seed ???

[vibhu_kk]

@varunriyer
how about the How many integers greater than 999 but not greater than 4000 ?

and the question on Seed ???



darn i took 4000 as 40,000 and tried solving the question, screwed a sitter

Puys anyone for f(x)=ax^2+bx+c f(5)=-3f(2).....
my answer was -4!!!!!!!!!

[bkd.exe]

Originally Posted by varunriyer

how about the How many integers greater than 999 but not greater than 4000 ?

and the question on Seed ???

i got 376 integers ..
I think its correct....
PLZZ SUM1 confirm the horsewala set....

[siauniverse]

999 t0 4000 answer is 376

[vampire4dracula]

integers between 999 and not greater than 4000 will be....
1*4*5*5*5 (*multiply) = 500
- - - - - -

minus.....
1*1*5*5*5............... 125 (since no number greater then 4000 will be excepted)

+ 1(4000 exception)

so the answer is 500-125+1=376....(i did 375 )