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Quantitative questions a day 51 to 100 - The discussions

I'm starting a new thread as the discussions will happen on this new thread for next 50 questions and the sectional test :-) Happy solving :smiley:
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HI all

I am new to PG can some body mail me the qns from 50 to 100. Or id any link is available for archives can some one post it. Thanks in advance.

My mail id is pradeep.gorai@cgi.com

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Hi I joined in late ,so if somebody can post/mail me all the questions from 1-100 of AQQAD with its respective solution,I will be highly gr8ful
Regards,
Akrant
akrant@gmail.com

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oye me not getting ANY quant question. are the questionssupposed to be mailed everyday (as the name of the thread suggests) to the people who have enrolled for the same? if true, there's some problem somewhere to be solved. i registered a loooong time back.

ne suggestions.....fellow PGites?

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hi guys i m new to this site i joined this forum and i recieve questions by mail but the main cause of worry for me is that i m not able to crack this questions can u tell me is this the level of questions appearing in cat

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bhai apna bhi 20/3 ans hai
i too joined the majority!!!!!!!!!!!!!
anybody having sectional test 01 questions and ans ???????????????
Pls mail me at ................
:wow: Mein aapka bahut abhari rahunga
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Quagmire Says
Shouldnt ur first eqn be 9 = (18/x-v) - (18/x+v)? Because x-v is going to be smaller than x+v, so 18/x-v > 18/x+v

Thanks a lot yaar, i did a very stupid error.Vaise we are on the wrong thread:) see you on the other one!!
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hi guys ..this is my first post at PG ...
My answer is also 20/3

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me also getting as option a - 20/3

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Question 101:
At his normal speed, Shirish can travel 18 km downstream in a fast flowing stream in 9 hours less than what he takes to travel the same distance upstream. The downstream trip would take 1 hour less than what the upstream trip would take provided he doubles his rate of rowing. What is the speed of the stream in km/hr?

(a) 20/3 (b) 8 (c) 33/4 (d) none of the foregoing


I am getting speed of stream as either zero(0) or negative(-20/3).
9=18/(x+v)-18/(x-v)
and
1=18/(2x+v)-18/(2x-v)
where x and v are speeds of Sirish and stream, respectively.
on calculating first one the relation is: x^2=v^2-4v
and then putting in second and solving.
Am i wrong somewhere??


Shouldnt ur first eqn be 9 = (18/x-v) - (18/x+v)? Because x-v is going to be smaller than x+v, so 18/x-v > 18/x+v
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18/(x-y)-18/(x+y) =9 =>2y/x^2-y^2=1/2(x spped of rowin,y speed of stream)
18/(2x-y)-18/(2x+y)=1=>2y/4x^2-y^2=1/18

hence 2y=(x^2-y^2)/2 =(4x^2-y^2)/18

from (x^2-y^2)/2 =(4x^2-y^2)/18 we get 5x^2=8Y^2 =>5(x^2-y^2)=3y^2=>x^2-y^2=3/5*y^2
put ths vaue in eqn 2y/x^2-y^2=1/2 u get 10y/3y^2=1/2 =>y=20/3

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Question 101:
At his normal speed, Shirish can travel 18 km downstream in a fast flowing stream in 9 hours less than what he takes to travel the same distance upstream. The downstream trip would take 1 hour less than what the upstream trip would take provided he doubles his rate of rowing. What is the speed of the stream in km/hr?

(a) 20/3 (b) 8 (c) 33/4 (d) none of the foregoing


I am getting speed of stream as either zero(0) or negative(-20/3).
9=18/(x+v)-18/(x-v)
and
1=18/(2x+v)-18/(2x-v)

where x and v are speeds of Sirish and stream, respectively.
on calculating first one the relation is: x^2=v^2-4v

and then putting in second and solving.
Am i wrong somewhere??
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hi me too getting the same answer, i approached with some steps like taking p=q=r=1 and then from the options was able to get the option 3). One help guys quote]

i think th question says there exists three DISTINCT real nos p,q & r.
whereas u took all of then as 1....??:
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ONE HELP

guys pls could anyone forward the quatz quetion a day mails before question #89...it will be of gr8 help to me... thnx in advance..

U can get some of the Qs here....

http://pagalguy.com/newsletter/archive.php?ArchiveID=MTE%3D
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amar_kashyap Says
Abhi mil gaya na answer, m=-n^2...But, its lil long..let's see if we can find some different approach...



ONE HELP

guys pls could anyone forward the quatz quetion a day mails before question #89...it will be of gr8 help to me... thnx in advance..
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mpq+nq=1
mqr+nr=1
mpr+np=1
i took value of q from 1st eq..
put it in 2nd .
den d value of r frm 2nd eq n put it in 3rd one..

it was a long method.. n made mistakes too...


Abhi mil gaya na answer, m=-n^2...But, its lil long..let's see if we can find some different approach...
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