I'm starting a new thread as the discussions will happen on this new thread for next 50 questions and the sectional test :-) Happy solving :smiley:

Follow this discussion to get notified of latest updates.

Nice! Like it on Facebook so that your friends can join you here.

Order by:
New Posts

Page 1 of 73

Q- in an examination, the maximum marks for each of the three papers is 50 each. the maximum marks for the fourth paper is 100. find the number of ways with which a student can score 60% in aggregate.

a) 330850 b)233551 c) 110551 d) 220800 e) none of these

hi........:grin:

Commenting on this post has been disabled.

One Year PGPM @ Great Lakes

**Post Graduate Program in Management (PGPM)**

- 1 Year Fast Track MBA Program

- Accredited by AMBA, UK

- Ranked 7th by Outlook & Business Today in 2014

- Avg. CTC of INR 11.43 Lakhs in 2014

**App. Deadline: 30 November, 2014**

10+ Global Associations with Leading Schools/ Universities

25+ International Visiting Faculty from Stanford, Yale, Kellogg, etc.

50+ National Level Prizes Won by Students in 2013-14

100+ Industry Leaders on Campus in 2013-14

3000+ Alumni Network spread over 28 Countries

Know MoreYa I'm aware of that formula for GP..thanks :)actually I was confused coz I assumed that there are 6 terms in GP including 4 GM....Any luck in solving Quant q 98 that I had posted earlier...

MaskedMenace Saysyeah...for a gp common ratio is term2/term1 ....nd it remain same through out d series...tht is wht i hav done....if not clear just revert

Commenting on this post has been disabled.

this is regd following q :

Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

hey just one query....regd the way u calculated common ratio..

I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth term as 128 and n =6we get common ratio as : 4....In your Method what I found dubious was that equaiton that you have formed....can you elaborate it a bit....coz assumin " x" is common ratio I thnk that equation can't be formed....

yeah...for a gp common ratio is term2/term1 ....nd it remain same through out d series...tht is wht i hav done....if not clear just revert

- 1 Like

Commenting on this post has been disabled.

this is regd following q :

Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

hey just one query....regd the way u calculated common ratio..

I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth term as 128 and n =6we get common ratio as : 4....In your Method what I found dubious was that equaiton that you have formed....can you elaborate it a bit....coz assumin " x" is common ratio I thnk that equation can't be formed....

Just find the common ratio..n keep multiplying it ...

this is how it can b done...

1/8, _ , _ , _ , _ ,128

Now,128/x = 8x == >x =4 (common ratio)

so, 1/8,1/2,2,8,32,128 ....3rd gm is 8..

- 1 Like

Commenting on this post has been disabled.

hello all,

quant Question no 98 :**------------------------------------------------------****Quantitative Question # 098****------------------------------------------------------ **

**Consider two distinct positive integers x and y having integer arithmetic, geometric and harmonic means. The minimum value of x - y is **

And my logic for solving this is described in my post above...but as per that I'm not able to get an answer...

Need help .....

Commenting on this post has been disabled.

Hello all,

I'm Deepa..

just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...

now goin by all this....lets consider even perfect squares like 4,16,36,64....and x&y; can be (2,2) ; (4,4) ; (-2,-2)....like wise and if we go by this method we can't get an answer....:...can sum1 sugg a way to solve it......

hoping for quick replies ;)..

i cldnt able to find q.no 98...please post tht ques...

Commenting on this post has been disabled.

Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

I kno its a simple question but just cant find the answer!

Just find the common ratio..n keep multiplying it ...

this is how it can b done...

1/8, _ , _ , _ , _ ,128

Now,128/x = 8x == >x =4 (common ratio)

so, 1/8,1/2,2,8,32,128 ....3rd gm is 8..

Commenting on this post has been disabled.

I'm Deepa..

just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...

now goin by all this....lets consider even perfect squares like 4,16,36,64....and x&y; can be (2,2) ; (4,4) ; (-2,-2)....like wise and if we go by this method we can't get an answer....:...can sum1 sugg a way to solve it......

hoping for quick replies ;)..

Commenting on this post has been disabled.

Bhaiyon Aur Behno,

Main QQAD subscribe karne ka param ichhuk hun. Meri iccha hai ki ek prashna pratidin pratah kal mere mail-box mein aaye. Maine subscribe karne ki link ki khoj ki lekin meri khoj asaphal rahi. Kya koi meri madad karna chahega?

Dhanyawad,

QQAD ka subscription pane ka param icchuk.

Commenting on this post has been disabled.

I kno its a simple question but just cant find the answer!

Commenting on this post has been disabled.

The palindromes in increasing order are

1

2

3

...

9

11

22

33

...

99

101

111

121

131

...

191

202

212

222

...

We see that the prime difference can be either 2 or 11 - hence the answer is (3)

Commenting on this post has been disabled.

Commenting on this post has been disabled.

..i too got 20/3..

Commenting on this post has been disabled.

Question 101:At his normal speed, Shirish can travel 18 km downstream in a fast flowing stream in 9 hours less than what he takes to travel the same distance upstream. The downstream trip would take 1 hour less than what the upstream trip would take provided he doubles his rate of rowing. What is the speed of the stream in km/hr?

(a) 20/3 (b) 8 (c) 33/4 (d) none of the foregoingI am getting speed of stream as either zero(0) or negative(-20/3).9=18/(x+v)-18/(x-v)and1=18/(2x+v)-18/(2x-v)where x and v are speeds of Sirish and stream, respectively.on calculating first one the relation is: x^2=v^2-4vand then putting in second and solving.Am i wrong somewhere??

yup... its comin out to be...20/3

:

Commenting on this post has been disabled.

When you follow a discussion, you receive notifications about new posts and comments. You can unfollow a discussion anytime, or turn off notifications for it.

183 people follow this discussion.
0Comments »new comments