About this discussion

Please continue here with all the quant queries and their discussions. link to previous thread :- http://www.pagalguy.com/forum/quantitative-questions-and-answers/72542-official-quant-thread-cat-2011-a.html :cheerio: :cheerio: :c...

Follow this discussion to get notified of latest updates.

Nice! Like it on Facebook so that your friends can join you here.

Order by:
New Posts

Page 26 of 610

Six couples together went for a picnic .Among them the husbands are -Amit,Sandeep,Rahul,Bobby and Mukesh .and the wives are - Madhuri, Jaya ,Sridevi ,Rani ,Tanuja ,Sharmila.

!!

6 ladies and only 5 gentlemen, how do they make 6 couples ?

is it 382,

first round-2 minutes

second round - 4 minutes

nth round 2^n minutes

6th round 64 minutes

we need to find number of times they meed in 7th and 8th round

during 7th round they would meet 127 times

and 8th roung they would meet 255 times

127+255=382

whats the OA

OA is 382

- 1 Like

Commenting on this post has been disabled.

Admissions open at Goa Institute of Management

Studying at GIM will change you; transforming you into a competent leader. A learning experience based on Ethics, Diversity, Innovation, Research and Social Sensitivity, specifically designed to launch you into a rewarding and successful career.

Learn more about us.

Start Downloading
Varun Tyagi
@varun.tyagi
14,220

IIFT-2009 paper

1/1.2.3 + 1/3.4.5 + 1/5.6.7 + ......................

M Stucked after partial fractions

1/2[1/(2n-1) - 1/n + 1/(2n+1)]

Plz suggest upon

S = 1/1.2.3 + 1/3.4.5 + .....

S = Summation of {1/2 [ 1/(2n-1) - 1/n + 1/(2n+1)] }

We know that Integration of dx/x = ln(x)

S = 1/2 [ (1/2) * ln(2n-1) - ln (n) + (1/2) * ln(2n+1) ] , where n ~ infinity

S = 1/4 { ln [(2n-1)*(2n+1)/n^2] }

S = 1/4 [ln (4 -1/n^2) ] , where n ~ infinity

Therefore S =

Commenting on this post has been disabled.

Jai Mehra
@jaikishan.n
1,520

Two motorists Anil and Sunil are practicing with two different sports cars: Ferrari and Maclarun, on the circular racing track, for the car racing tournament to be held next month. Both Anil and Sunil start from the same point on the circular track. Anil completes one round of the track in 1 minute and Sunil takes 2 minutes to complete a round. While Anil maintains same speed for all the rounds, Sunil halves his speed after the completion of each round. How many times Anil and Sunil will meet

between the 6th round and 9th round of Sunil (6th and 9th round is excluded)? Assume that the speed of Sunil remains steady throughout each round and changes only after the completion of that round.

260347382None of these

Plz share the approach as well.

is it 382,

first round-2 minutes

second round - 4 minutes

nth round 2^n minutes

6th round 64 minutes

we need to find number of times they meed in 7th and 8th round

during 7th round they would meet 127 times

and 8th roung they would meet 255 times

127+255=382

whats the OA

- 1 Like

Commenting on this post has been disabled.

Two motorists Anil and Sunil are practicing with two different sports cars: Ferrari and Maclarun, on the circular racing track, for the car racing tournament to be held next month. Both Anil and Sunil start from the same point on the circular track. Anil completes one round of the track in 1 minute and Sunil takes 2 minutes to complete a round. While Anil maintains same speed for all the rounds, Sunil halves his speed after the completion of each round. How many times Anil and Sunil will meet

between the 6th round and 9th round of Sunil (6th and 9th round is excluded)? Assume that the speed of Sunil remains steady throughout each round and changes only after the completion of that round.

260347382None of these

Plz share the approach as well.

speed is halved so time is doubled

7th round takes 2^7 mins

8th round takes 2^8 mins

2^7+2^8=384

Commenting on this post has been disabled.

Six couples together went for a picnic .Among them the husbands are - Amir,Sandeep,pradeep ,Rahul,Bobby and Mukesh .and the wives are - Madhuri, Jaya ,Sridevi ,Rani ,Tanuja ,Sharmila .

In the picnic, while they were playing a game ,all of them divided into six teams -Coconut, Jackfruit,Banana ,Orange ,Mango and Pineapple .No person was in the same team as his/ her spouse ,also each group consists of exactly two persons .We know the following information about them ,

(1)Amir and Sandeep's wife were in the same team .Rahul was in the team Coconut but neither Tanuja nor Sridevi was in that team .

(2) Pradeep , whose spouse was in team Orange, and Tanuja were in the same team

(3)Sandeep is the husband of Sharmila ,who was in the team Banana

(4)Mukesh and Rani were in the team Jackfruit and none of their spouses was in Orange or Coconut team

(5)Jaya and Sridevi 's husband were in the same team,Sridevi and jaya's husband were in the same team ,and one of these groups was pineapple

(6) Madhuri's spouse was in the team Mango

Q1)who is the husband of Sridevi ??

(1) rahul (2) bobby (3)pradeep (4)amir (5) cannot be determined

Q2) who is the wife of mukesh ??

(1) Madhuri (2)Rani (3) Sridevi (4)Jaya (5) Tanuja

Q3) who was in the same team as bobby's spouse ??

(1) rahul (2) Amir (3) pradeep (4) Mukesh (5) bobby

plzz post the approach !!

Commenting on this post has been disabled.

between the 6th round and 9th round of Sunil (6th and 9th round is excluded)? Assume that the speed of Sunil remains steady throughout each round and changes only after the completion of that round.

Plz share the approach as well.

Commenting on this post has been disabled.

Subhashdec2 SaysWhat are the options???

Method batao yaar options kya karna

Commenting on this post has been disabled.

Ignoramus Totalus
@retry
1,980

IIFT-2009 paper

1/1.2.3 + 1/3.4.5 + 1/5.6.7 + ......................

M Stucked after partial fractions

1/2

Plz suggest upon

if i remember correctly, this question had options using e and logs involved, so

going by partial fractions are probably not the way to go ..s

summing first 3 terms ..

1/1.2.3 + 1/3.4.5 + 1/5.6.7 = 1/6+1/60+1/210 = .16 + .016 +.004 ~ .18

next term is 1/7.8.9 ~ 1/504 ~ .002 can be neglected ..

EDITING .. here are the options ..

e^2 -1 ~ 2.7^2 - 1 -- nowhere close

ln 2 -1 -- .693 - 1 .. negative !

2log2 - 1 = 2*.301 -1 .. negative !

option D - none of these. .

aur koi method ho toh batao yaar .. i admit that though this is a very kaam chalau method .. i find myself doing this in every series question of this type

Commenting on this post has been disabled.

IIFT-2009 paper

1/1.2.3 + 1/3.4.5 + 1/5.6.7 + ......................

M Stucked after partial fractions

1/2

Plz suggest upon

Such questions are best solved using options,

please provide options and I will try and tell you a way to solve such questions.

Gaurav Rohella | XIMB-PGDM(2012-14) | Core Member Illuminatix | Media and PR Cell, XIMB

Commenting on this post has been disabled.

Varun Tyagi
@varun.tyagi
14,220

9*(ab)*(cde) =abcde

where ab 2 dig no

cde 3 dig no

abcde 5 dig no

Find ab and cde

9 * (ab) * (cde) = abcde

=> 9 * (ab) * (cde) = 1000ab + cde

We can observe that 9*b*e gives 'e' as the unit digit which means that either 'b' is 9 or 'b' is 4

We have 9 * (10a+9) * (cde) = 1000(10a+9) + cde

we can rearrange to form the equation as

(cde) = (1000a + 900)/(9a+8 )

for any value of 'a' R.H.S is not an integer value.....Hence b != 9

We have 9 * (10a + 4) *(cde) = 1000(10a+4) + cde

We can rearrange to form the equation as:

cde = (2000a + 800)/(18a+7)

For a = 1 cde =112

Now Verify

We found out that a = 1, b = 4 and cde =112

9*(14)*(112) =

- 3 Likes

Commenting on this post has been disabled.

Neetujain1987 SaysStill I didnt get whese 2 traingle are similar.

let angle adp=a

apd=90-a

in triangle apx

x is the point of intersection of dp and ar

xpa=apd=90-a

xap=rap=a

in triangle bar

rap=a

bra=90-a

hence adp~bar

Commenting on this post has been disabled.

Subhashdec2 Saysactually it is ADP~BAR

Still I didnt get whese 2 traingle are similar.

Commenting on this post has been disabled.

IIFT-2009 paper

1/1.2.3 + 1/3.4.5 + 1/5.6.7 + ......................

M Stucked after partial fractions

1/2

Plz suggest upon

What are the options???

Commenting on this post has been disabled.

1/1.2.3 + 1/3.4.5 + 1/5.6.7 + ......................

M Stucked after partial fractions

1/2

Plz suggest upon

Commenting on this post has been disabled.

When you follow a discussion, you receive notifications about new posts and comments. You can unfollow a discussion anytime, or turn off notifications for it.

453 people follow this discussion.
0Comments »new comments