Hey Junta!!! Good Morning!!! Hope u are all doing GREAT...am starting this section as a common thread for my queries in MATH...all others are invited to solve..to help around..to post thier own questions.... Hey Mods..if u think..this ma...

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@vijay317
164

hmmm...

achcha luk at this....

131^4%300=(300-169)^4%300.

expansion parr,

odr than last term, all will be div by 300...

so,

-169 remains..

300-169=131.

????

wats rong here?

Last term in binomial expansion is not -169 but (-1)^4*4c4*(169)^4

So last term is (169)^4

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@chiya
309

131^4 %300

Hmm this might not b acceptable but.lets c:

131^2 = 17161 = 300 * 57 + 61

So 131 ^4 %300 = 61 ^2 %300 = 3721 % 300 = 121 :)

hmmm...

achcha luk at this....

131^4%300=(300-169)^4%300.

expansion parr,

odr than last term, all will be div by 300...

so,

-169 remains..

300-169=131.

????

wats rong here?

Commenting on this post has been disabled.

@vijay317
164

Hmm this might not b acceptable but.lets c:

131^2 = 17161 = 300 * 57 + 61

So 131 ^4 %300 = 61 ^2 %300 = 3721 % 300 = 121 :)

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@chiya
309

1331^4 % 300 is wat we need.

So 1331 = 300*4 +131

So (300*4+131)^4 % 300 = 131 ^ 4 % 300

Got it chiya?

I think i can kick myself right now!!

subtacted 1200 from 1331 in my head and got a grand total of 231..fir socha in any case i nevah figure out naything here, so me gotta be rong!!

this is the nuksaanz of having a low self confidence, see!

But,ab i cant figure out last step either:confused:

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@vijay317
164

hey ppl i was juss goin thru the thread......

can anyone plz temme how 1331^4 becumz 131^4?

1331^4 % 300 is wat we need.

So 1331 = 300*4 +131

So (300*4+131)^4 % 300 = 131 ^ 4 % 300

Got it chiya?

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@chiya
309

Another one...got it from the previous post.

(17^24)%300

= (300-11)^12 % 300

= 11^12 % 300

= 1331^4 % 300

= 131^4 % 300

= 121.

:)

hey ppl i was juss goin thru the thread......

can anyone plz temme how 1331^4 becumz 131^4?

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@chetna
181

Using Appo. theorum

AB^2+AC^2=2(x^2+BD^2)

Now BD=CD=5

AB^2+AC^2=2(x^2+25)

Using 1 AB=3a AC=4a

25*a^2=2x^2+50

1st option is not enuf

using 2 option also we have 25a^2=100

a=2 ...

Using 2nd option alone it can be solved x=5

hmmmm nice one.....:)

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(1) DS ( can be answd using one statement alone? either statement? both the statements together? question cannot be answd ?

what is the length of median to BC in triangle ABC ? (given that BC = 10)

I. AB : AC = 3:4

II. triangle ABC is a right angled @ A. )

Using Appo. theorum

AB^2+AC^2=2(x^2+BD^2)

Now BD=CD=5

AB^2+AC^2=2(x^2+25)

Using 1 AB=3a AC=4a

25*a^2=2x^2+50

1st option is not enuf

using 2 option also we have 25a^2=100

a=2 ...

Using 2nd option alone it can be solved x=5

[QUOTE=(2) A rabbit is 500m away from ahole. an eagle which is horizontally 1.5km away from the rabbit immediately swoops down with speed of 54km/hr at an angle of 30degree to catch the rabbit. the rabbit also starts running towards the hole so that the eagle is behind the rabbit and both are running in the same direction. in between, the eagle realizes that its direction is not correct so changes its angle at 60 degree and just catches the rabbit. If distances travelled by the eagle at 30degree and 60degree are same, then find the speed of the rabbit.

for 2nd one refer to attached diagram

AC=1500

CB=500

AD=BD=X

AB=500SQRT(10)

BD=AC/SQRT(3)

sO TOAL DISTANCE TRAVELLED BY EAGLE IS =1825.74 METERS

TIME=121.76 SECS

SPEED OF HARE =500/121.76=4.1 METERS

( : eagles_dare , ur renumeration ? )

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(1) DS ( can be answd using one statement alone? either statement? both the statements together? question cannot be answd ?

what is the length of median to BC in triangle ABC ? (given that BC = 10)

I. AB : AC = 3:4

II. triangle ABC is a right angled @ A.

(2) A rabbit is 500m away from ahole. an eagle which is horizontally 1.5km away from the rabbit immediately swoops down with speed of 54km/hr at an angle of 30degree to catch the rabbit. the rabbit also starts running towards the hole so that the eagle is behind the rabbit and both are running in the same direction. in between, the eagle realizes that its direction is not correct so changes its angle at 60 degree and just catches the rabbit. If distances travelled by the eagle at 30degree and 60degree are same, then find the speed of the rabbit.

( : eagles_dare , ur renumeration ? )

Commenting on this post has been disabled.

@ankursanghi
29

catasp2005 SaysWhats 'p' for????? M i missinng sumthing or is it not mentioned???

Even I don't know what it means... this question is from WebSprint from CL...

The only further information on this is the following four choices. Let me also know if you make meaning of this:

greater than p/4 and less than 1 greater than 1 and less than 2 greater than 2 less than p/4

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There is a circle of radius 1 cm. Each member of a sequence' of regular polygons S1(n), n = 4, 5, 6,..., where n is the number of sides of the polygon, is circumscribing the circle; and each member of the sequence of regular polygons S2(n), n = 4, 5, 6,... where n is the number of sides of the polygon, is inscribed in the circle. Let L1(n) and L2(n) denote the perimeters of the corresponding polygons of S1(n) and S2(n).

Then {L1(13) + 2p}/L2(17) is

Whats 'p' for????? M i missinng sumthing or is it not mentioned???

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@ankursanghi
29

There is a circle of radius 1 cm. Each member of a sequence' of regular polygons S1(n), n = 4, 5, 6,..., where n is the number of sides of the polygon, is circumscribing the circle; and each member of the sequence of regular polygons S2(n), n = 4, 5, 6,... where n is the number of sides of the polygon, is inscribed in the circle. Let L1(n) and L2(n) denote the perimeters of the corresponding polygons of S1(n) and S2(n).

Then {L1(13) + 2p}/L2(17) is

Then {L1(13) + 2p}/L2(17) is

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hey thanks a lot both of u

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@thakarsagar
135

(17^24)%300

= (300-11)^12 % 300

= 11^12 % 300

= 1331^4 % 300

= 131^4 % 300

= 121.

:)

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