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Hi Guys, Geometry, Algebra and Number system form the major chunk of our QA section for CAT. Proficiency in these three sections would definitely boost our Quants scores. Contents of Geometry 1\. Plane Geometry - Basics and Tri...

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I am new to this forum and this is my first post. Please provide solution for this question I stumbled upon

The question is in the attached image

a. 8/5b. (1 + sqrt(2))/2c. 2 - sqrt(2)d. 4/5

Let center of the middle circle be O.

Drop perpendicular OP on ED

OP BC

So, AO/AB = OP/BC

=> 3/5 = OP/1 or OP = 3/5

Apply pythagoras thm. in triangle OPD

OD = OP + PD

1 = 9/25 + PD

PD = 16/25

PD = 4/5

And, DE = 2*PD = 8/5

Ques in the attached image. Options are:

a. 152/3b. 32c. 12d. 41

http://cdn.pagalguy.net/s/forum/files/2/5/1/7/3/5/22001/attach/Triangles.jpg

This has been done earlier. Credits to chillfactor bhai who solved it. Here's the original solution. Last post on this page :

http://www.pagalguy.com/discussions/official-quant-thread-for-cat-2011-part-2-25067094

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Ques in the attached image. Options are:

** a. 152/3 **

** b. 32 **

** c. 12 **

** d. 41**

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The question is in the attached image

** a. 8/5 **** b. (1 + sqrt(2))/2 **** c. 2 - sqrt(2) **** d. 4/5 **

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In the attached figure , if BC : CD = 2:3 and AE : EC = 3:4. Find the ratio of the area of triangle ECD to the area of triangle AEB

Ans: 2:1

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Originally Posted by nramachandran160.

SET - 9

An equilateral triangle ABC of side 40 cm is cut into two pieces in such a way that one piece is an equilateral triangle containing the vertex A and the second piece is a trapezium. Two such trapeziums are placed beside each other to form a parallelogram. What is the perimeter (in cm) of the parallelogram?

a. 120

b. 160

c. 200

d. 240

new equilateral triangle ki side = 20

Suja

Can anyone explain this que ?

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Is there any1 who knows the concept of polygon inside polygon? Its done in byju's class but i cudnt attend tat session...pls post it here by u knw the concept.

Thnx in advance.

I don't know how relevant this is to the CAT prep. but it's highly unlikely that such concepts would ever figure ,as questions, in the CAT.

In case you wish to know more on this concept,do get a book on 'Trigonometry' By S L Loney...all such ( and many more) concepts are given there towards the end of the book.Hope that helps

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Find me here : https://www.facebook.com/amit.sriv

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SET-24

A question from the recent mockThe shape of a solid plastic toy is shown in the figure given below. The structure consists of a cylinder, frustum of a cone and a hemisphere. The height and radius of the cylinder are H/2 and r respectively. The radius of the hemisphere is R. The height and base radius of the original cone were H and R respectively. If H = 2R = 4r, then what is the volume of the toy?

a

b

c

d

converting all volumes in terms of r

ans comes 'a'

Total volume = v(hemisphere) + v(cylinder) + v(large cone) - v(small cone)

=(2/3)(R^3)+ r^2h + (1/3)(R^2)H - (1/3)(r^2)h

put H = 2R = 4r, h = H/2

=

= 12r^3

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A question from the recent mock

a

b

c

d

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VIVEK SINGH
@vivekmohit
1,004

Thnx in advance.

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ashishkakkar123 Saysguys like in equilateral triangle orthicentre= in centre = centrod=circumcentre. does isocles triangle follow this property as perpendicular bisector , median ,angle bisector altitude of it are same as n equilateral triangle....

I think no , because intersection point of medians is different than that of altitudes

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guys like in equilateral triangle orthicentre= in centre = centrod=circumcentre. does isocles triangle follow this property as perpendicular bisector , median ,angle bisector altitude of it are same as n equilateral triangle....

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160.

new equilateral triangle ki side = 20

Suja

errrr..

new eq. ki side can be anything (as whenever we draw a parallel line to the the 3rd side we get an eq. tri.)

Its another matter that the perimeter of the formed llgm will be fixed (160)

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barclays_boss SaysOk solve this :

Join PQ. OP = 2 using distance formula. => OQ = 2

In triangle OPQ, by pythagoras thm. PQ = 2(sqrt2)

By distance formula,

PQ = (s+sqrt3) + ( t-1) = 8

s +2(sqrt3)s +3 +t -2t + 1 =8---(1)

Also, s + t = 4--------(2)

So, (sqrt3)s = t ...................from (1) and (2)

substitute this value in (2)

So, 4s = 4

s = 1

s = 1

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barclays_boss SaysOk solve this :

I got

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Ok solve this :

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