About this discussion

- © 2015-2016
- Careers
- Advertise
- Contact Us

Hi Guys, Geometry, Algebra and Number system form the major chunk of our QA section for CAT. Proficiency in these three sections would definitely boost our Quants scores. Contents of Geometry 1\. Plane Geometry - Basics and Tri...

Follow this discussion to get notified of latest updates.

Nice! Share it on Facebook so that your friends can join you here.

Order by:
New Posts

Page 16 of 32

SET-18The three sides AB, BC and CA of a triangle ABC are 7 cm, 10 cm and 12 cm long respectively. AB is extended to D and AD = 28 cm. BC is extended to E and BE = 20 cm. CA is extended to F and CF = 36 cm. What is the ratio of the area of triangle ABC to the area of triangle DEF?

Figure attached

i think the answer for set 18 is 1:18 not 1:17.

Commenting on this post has been disabled.

freakonomist Saysgot 1:17 as the answer , use area = 0.5* a*b*sin(t)

how did you get the angle?

Commenting on this post has been disabled.

Given the ball is 5 cm above the water level which means under the water the height of the ball is 10 cm.So the centre of the ball is under water and it is (7.5 - 5)cm i.e. 2.5 cm under the water. So applying simple pythagoras theorem, radius of the circular area will be sqrt of 7.5^2 - 2.5^2 = 5 root(2)

Thus circumference = 2pi*r = 10*pi*root(2)

Commenting on this post has been disabled.

noma SaysWhats the answer not able to solve...

got 1:17 as the answer , use area = 0.5* a*b*sin(t)

Commenting on this post has been disabled.

SET-18The three sides AB, BC and CA of a triangle ABC are 7 cm, 10 cm and 12 cm long respectively. AB is extended to D and AD = 28 cm. BC is extended to E and BE = 20 cm. CA is extended to F and CF = 36 cm. What is the ratio of the area of triangle ABC to the area of triangle DEF?

Figure attached

Whats the answer not able to solve...

Commenting on this post has been disabled.

Please find attachment with diagram.

Radius of the ball, OA = 5 root(5) (By Pythagorus theorem)

Circumference = 2*pi*r = 10 root(2)

Hope this is the answer.

Please mark your questions SET-wise, so that it would be easy to refer them. Thank you !

Please explain further not able to get why OA would be the new radius?

Commenting on this post has been disabled.

a ball of diameter 15 cm is floating so that the top the ball is 5 cm above the smooth surface of the pond .what is the circumference in cm of the circle formed by the contact of the water surface with the ball.

plz sove this ques

answer: 10* pi* root 2

Commenting on this post has been disabled.

a ball of diameter 15 cm is floating so that the top the ball is 5 cm above the smooth surface of the pond .what is the circumference in cm of the circle formed by the contact of the water surface with the ball.

plz sove this ques

is the answer 10root2 pi

Commenting on this post has been disabled.

a ball of diameter 15 cm is floating so that the top the ball is 5 cm above the smooth surface of the pond .what is the circumference in cm of the circle formed by the contact of the water surface with the ball.

plz sove this ques

Please find attachment with diagram.

Radius of the ball, OA = 5 root(5) (By Pythagorus theorem)

Circumference = 2*pi*r = 10 root(2)

Hope this is the answer.

Please mark your questions SET-wise, so that it would be easy to refer them. Thank you !

Commenting on this post has been disabled.

When you follow a discussion, you receive notifications about new posts and comments. You can unfollow a discussion anytime, or turn off notifications for it.

116 people follow this discussion.
0Comments »new comments