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What is the area of a parallelogram with an angle 45 degrees, height 4 cm and a diagonal 5 cm? Regards, Bharathi P.S: Please post your answers in the thread only after 6 PM., April 25 2003.

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The Pahadi Mod
@raghav507
51,572

closing this old thread.

please continue in this new thread for all the geometry related discussions.

http://www.pagalguy.com/discussions/geometry-for-cat-2011-25069681

----------wrong post--------------

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speedthestar SaysThe radius of an incircle of a triangle is 24cm and the segments in which one side is divided by the point of contact are 36cm and 48cm. Find the length of the smaller of two sides of the triangle.

the other two sides are 36+x and 48+x.

semi perimeter = 84+x

use the formula, r=(area of triangle)/(semi perimeter)

we get x = 42.

so length of smaller side = 36+42 =

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ABCD is a trapezium such that abcd. Angle A and B are equal and 45 degree.

if the perimeter is 40cm. what can be the maximum area of the trapezium

Let distance between the two parallel sides be 'x' and let one of the sides be 'a', then the other parallel side is x+a+x = a+2x. The two non-parallel sides will be x*sqrt(2). So (as perimeter = 40) 2x+2a+(2*sqrt(2)*x) = 40

=> x+a=20

area of the trapezium = x(a+x). Substituting 'a' we get

area = 20*x-. Differentiate area w.r.t 'x' to get x= 5*(sqrt(2))

so area =

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The radius of an incircle of a triangle is 24cm and the segments in which one side is divided by the point of contact are 36cm and 48cm. Find the length of the smaller of two sides of the triangle.

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kuldeep kumar
@culdip
7,460

A rhombus OABC is drawn inside a circle, whose centre is at O, in such a way that vertices A,B,C of the rhombus are on the circle. If the area of the rhombus is 32* sqrt(3) cm. Find the radius of the circle

draw the line OB. We get 2 equilateral triangle OAB and OCB

NOW supose the radius is r

area of rmbs = 2(rt3/4*rsqr) =32*sqrt3

r=4

ans

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kuldeep kumar
@culdip
7,460

DJ Harry SaysQ. ABC is a equilateral triangle inscribed in a circle of radius r. What is the area of the largest square that can be inscribed inside it?

ans is (63-36root3)rsquire

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kuldeep kumar
@culdip
7,460

if the perimeter is 40cm. what can be the maximum area of the trapezium

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kuldeep kumar
@culdip
7,460

Junta help solving theseABC is a triangle, D lies on the side BC and E lies on the side AC. AE = 3, EC = 1, CD = 2, DB = 5, AB = 8. AD and BE meet at P. The line parallel to AC through P meets AB at Q, and the line parallel to BC through P meets AB at R. Find area PQR/area ABC.

1.

Triangle APM has A = 90o and perimeter 152. A circle center O (on AP) has radius 19 and touches AM at A and PM at T. Find OP.

2.

please tell me solution

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DJ Harry SaysQ. ABC is a equilateral triangle inscribed in a circle of radius r. What is the area of the largest square that can be inscribed inside it?

Side of the triangle = a = r*sqrt(3)

now there can be only one square in the equilateral triangle. Let its side length be 'x'.

clearly tan(60) = x/ = 2x/(a-x)

So, on solving we get

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