- © 2015-2016
- Careers
- Advertise
- Contact Us

Is ab an even number ? I. a is divisible by 3. II. (b+1) is divisible by 4. The correct answer it says is II, how?? If x^a = y^b > z^c, is x = y > z? I. a = b > c II. a = b = c The answer is III, how?? If n is a n...

Follow this discussion to get notified of latest updates.

Nice! Share it on Facebook so that your friends can join you here.

Order by:
New Posts

Page 1 of 2

-----------------------------------------------------------------------------

I know some of my question are dumb but ....er....well, I am dumb too.

Please show me how to solve this DS question.

Given that x and Y are non-negative. What is the value of X?

I 2X+2Y=20

Statement 1 -

2x+2ythat is x+y

(5+15=20 , 8+12=20..... )

so nothing can be said abt the value of x

Statement 2 -

x-2y>=20

(30-2*5=20,40-2*9=22)

so nothing can be said abt the value of x

now combining both the statements .....

we know that both x,y are non negative

and still

x+y = 20 (limiting case ...drop the x-2y = 20(limiting case ....drop the > sign)

we now x = 20 and y = 0

no other solution will satisfy ....u can have a try

so the answer is 3 ( i.e we have to use both the statements to get the answer)

HTH

Gautam

Commenting on this post has been disabled.

-----------------------------------------------------------------------------

Commenting on this post has been disabled.

@bhars18
147

ab = 10a + b

Aha...! Never thought of this perspective :). I always assumed ab was the product of a and b and not as two digits of the number. I guess it cannot be assumed unless specified :)

Bharathi.

Commenting on this post has been disabled.

Hi,

ab = 10a + b

10a is even.

b+1 is div by 4 --> b is odd.

so even + odd = odd

So only ii is enough to answer

- 2 Likes

Commenting on this post has been disabled.

Hi bhars,

i think the ans is III...i.e the Q can be answered by using both the statements together.

cos...

(a) implies tat '#' cud b '+' or '-'

(b) implies tat '#' cud b '+' or '*'

so no definite ans considering the statements individually,BUT if we combine them

then '#' sign surely represents '+'...n then we can find the value of 10#20 i.e 10+20=30

regards,

Commenting on this post has been disabled.

@bhars18
147

If the symbol # represents one of the following operations: addition, subtraction , multiplication or division, what is the value of 10#20?

a.2#0 =2

b.2#2 = 4.

:) Bharathi

Commenting on this post has been disabled.

@shub001
27

When dealing with powers, you should see a few things.

(i) The sign of those numbers

(ii) whether the powers are odd or even

(iii) If the numbers are 1.

Thanks for this tip.

Commenting on this post has been disabled.

@bhars18
147

Is ab an even number ?

I. a is divisible by 3.

II. (b+1) is divisible by 4.

All u can say is b is odd. a could be odd (in which case ab would be odd) or a could be even(in which case ab would be even). Answer as said by Arcade, is 4.

If x^a = y^b > z^c, is x = y > z?

I. a = b > c

II. a = b = c

When dealing with powers, you should see a few things.

(i) The sign of those numbers

(ii) whether the powers are odd or even

(iii) If the numbers are 1.

Only if all of these are given directly or indirectly, we can solve the problem. Since NOTHING has been said about x, y and z (whether integers, fractions

Bharathi.

Commenting on this post has been disabled.

hi

i think the answer 2 the first question shud b choice 3.. from second option we get b is an odd number.. but we don't know anthg abt a.. it can even b a frction.. from the fact that a is a multiple of 3, we know that a is also an integer. so we can safely say that ab will b odd...

Commenting on this post has been disabled.

When you follow a discussion, you receive notifications about new posts and comments. You can unfollow a discussion anytime, or turn off notifications for it.

9 people follow this discussion.- CAT 2015 Applications & Online Registration
- CAT • 12:00 AM, 06 Aug '15

- India International Animation and Cartoon Film Festival (IIACFF)
- CAT • Thursday, 1 Oct

0Comments »new comments