Last updated

Author
vinoj sagar @hi5blast

Tags

# Data Suffciency Thread for CAT 2011

Hi All, I think there is no Data Sufficiency thread in PG.So Iam creating this Thread dedicated only to Data Sufficiency Questions and Fundas.So why wait Let Start :: :: Regards
Order by:
Page 2 of 6
A man has 57 pens. He wants to distribute these pens among his 3 sons such that his eldest son receives the highest number of pens. What will be the number of pens received by the eldest son?

A. The number of pens received by the sons are in Arithmetic Progression.
B. The number of pens received by the sons are in Geometric Progression.

Taking A) let the no of pens be a-d,a,a+d
so, a-d+a+a+d=57, therefore, a=19
AP is 18 19 20 ..eldest son gets 20

Taking B) 1 7 49 are in GP..so eldest son gets 49

Ques can be answered using either of the A or B.

correct???
Commenting on this post has been disabled.
Question can not be answered even by using both the statements together.

Suppose, we take statement A:
Then the middle aged son gets 19 pens. But, we can't predict about the other two sons' possessions.

From statement B:
let say they have a, ar, ar^2 no of pens
so, a(r^3 - 1)/(r-1) = 57
or, a(r^2 + r + 1) = 3 x 19 or 1*57
a cant be 19, so, a =3,
but using this we are not getting any integer value of r.
if a = 1 then we will get r = 7.
so, three numbers will be, 1,7,49

So, statement B alone can answer the question.
Please confirm in case of any aberrations.

Just try this combination 1, 7, 49. It satisfies.

One more set of values is possible. For the time being, I leave it upto you to find that

Please find my corrections in bold green. :splat:
I could not find out any other combination though. :shocked:

i think both A nd B r required..from a we get 19 wid common difference zero..wid B we get common ratio 1 so 19...any flaw plz point

The question is telling that the eldest son will receive the maximum no. of pens, So, it can be inferred that their possessions of pens will be different.
"If you want some, go get it. Period."
Commenting on this post has been disabled.

i think both A nd B r required..from a we get 19 wid common difference zero..wid B we get common ratio 1 so 19...any flaw plz point

Commenting on this post has been disabled.
Question can not be answered even by using both the statements together.

Suppose, we take statement A:
Then the middle aged son gets 19 pens. But, we can't predict about the other two sons' possessions.

From statement B:
let say they have a, ar, ar^2 no of pens
so, a(r^3 - 1)/(r-1) = 57
or, a(r^2 + r + 1) = 3 x 19
a cant be 19, so, a =3,
but using this we are not getting any integer value of r.
So, this statement is of no use.
And even by combining both of them we can not answer the question.

Please confirm in case of any aberrations.

Just try this combination 1, 7, 49. It satisfies.

One more set of values is possible. For the time being, I leave it upto you to find that
• 1 Like
Commenting on this post has been disabled.
A man has 57 pens. He wants to distribute these pens among his 3 sons such that his eldest son receives the highest number of pens. What will be the number of pens received by the eldest son?

A. The number of pens received by the sons are in Arithmetic Progression.
B. The number of pens received by the sons are in Geometric Progression.

Question can not be answered even by using both the statements together.

Suppose, we take statement A:
Then the middle aged son gets 19 pens. But, we can't predict about the other two sons' possessions.

From statement B:
let say they have a, ar, ar^2 no of pens
so, a(r^3 - 1)/(r-1) = 57
or, a(r^2 + r + 1) = 3 x 19
a cant be 19, so, a =3,
but using this we are not getting any integer value of r.
So, this statement is of no use.
And even by combining both of them we can not answer the question.

Please confirm in case of any aberrations.
"If you want some, go get it. Period."
Commenting on this post has been disabled.
A man has 57 pens. He wants to distribute these pens among his 3 sons such that his eldest son receives the highest number of pens. What will be the number of pens received by the eldest son?

A. The number of pens received by the sons are in Arithmetic Progression.
B. The number of pens received by the sons are in Geometric Progression.

can be said from statement A alone.
Commenting on this post has been disabled.
A man has 57 pens. He wants to distribute these pens among his 3 sons such that his eldest son receives the highest number of pens. What will be the number of pens received by the eldest son?

A. The number of pens received by the sons are in Arithmetic Progression.
B. The number of pens received by the sons are in Geometric Progression.
• 2 Likes
Commenting on this post has been disabled.
can be answered by (a) only.
as root(x)>y
so, x>(y^2) and x is always positive.
so, we can say that x>y (whether y is -ve or +ve)
but b says (x^3)>y,
here let x=2, y=1
then, x>y
now let x=2, y=7,
so, x

consider x=0.01 and y=0.02;

for this case root(x)>y and x 0.2 but 0.01

consider x=9 and y=2 ;
for this case root(x)>y and x>y ;
root (9)=3 > 2 and 9 >2 ;

So we cant say by using only 1st statement ... so we need to consider both statements to arrive at a conclusion ..
• 1 Like
Commenting on this post has been disabled.
guravus Says

Both the statements are required to answer the question.
here's the breakdown-
french(boy)+spanish(boy)=6+y(let)
frensh(girl)+spanish(girl)=x(let)+8
so, as per the first statement,
x+y=21.......(i)
as per the second statement,
8+yor, x>y+2,......(ii)
combining i and ii
it can be said that max(x)=12.
so, both statements are required.
the can be can not be determined also (confused), as the breakdown of boys and girls is not given. please post the OA
"If you want some, go get it. Period."
Commenting on this post has been disabled.
Q) Is x > y?

(1) x > y
(2) x^3 > y

can be answered by (a) only.
as root(x)>y
so, x>(y^2) and x is always positive.
so, we can say that x>y (whether y is -ve or +ve)
but b says (x^3)>y,
here let x=2, y=1
then, x>y
now let x=2, y=7,
so, x
"If you want some, go get it. Period."
Commenting on this post has been disabled.