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*This is a thread dedicated entirely to the problems faced by CAT Aspirants solving Nishit Sinha's Quant and LA/DI Book.* This thread will help CAt aspirants to understand the Basic concepts thoroughly for those who are using the book and wil...

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Page no:260,Maxima nd Minima....Q5.....f(x)=max(4x+3,3x+6) for x belongs to [-6,10]...I don't think the intrvl givn is crct...

- The answr given is 6....how cm???. 22 Jul '13.

ind remainder 2^45/73? guyz plz answer

- 9 Comments
- 41. 18 Jul '13.
- Is it 1 ?. 17 Jul '13.

Q1. A palindrome number of S digit, where S is even written in base N will be definitely divided by???

a) N-1

b)N+1

c)2N+1

- N+1. 31 Jul '13.
- N+1. 20 Jul '13.

1st 126 natural numbers are put side by side in the ascending order to form large number 123456.....123124125126. What will be reminder if it is divided by 5625.

1 Comments

Hasit

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Does somebody have Nishit Sinha Quantitative aptitude PDF Version ebook

- Free webinar on ' Art of problem solving in QA for CAT' b.... 13 Aug '13.

Free webinar on ' Art of problem solving in QA for CAT' by the experienced CAT faculty Mr. Nishit Sinha. Register free here - Limited Seats available so hurry up!

www.webartsol.com/registration/#...

This is an exclusive webinar which will be covering important Quant prep areas like:

Free Webinar: Tips on QA preparation for CAT 2013 : Quantitative : PaGaLGuY Forums

A Quick revision of important topics in QA

Find logical ways of solving the questions

Understand flaw detectors

Have a Q & A session with the author

Kindly provide approach for these..

N=123456.....125126. What will be the remainder when N is divided by 5625

a. 8 b. 10 c. 11 d.12

2. The smallest natural number which is a perfect square and is of the form "abb" lies in between:

a. 1000-2000 b.2000-3000 c.3000-4000 d.4000-5000

- Take N'=123456....125000 and then N=N'+126; Now N' is div.... 02 Sep '13.

Take N'=123456....125000 and then N=N'+126; Now N' is divisible by 625i.e., 25*25 as 125000is divisible 625. Now sum of the digits of N'=1+2+3+4+...+125=126*125/2=63*125 and so it is divisible by 9 as 63 is divisible by 9. 9 and 625 are prime to each other and hence N' is divisible by 9*625=5625. The remainder is 126.

Hi Puys, Help me on these questions....

1. What is the maximum value of HCF[(n^2+17),((n+1)^2+17)]

a. 69 b.85 c.170

2. What is the sum of digits of the least multiple of 13 ,which when divided by 6,8 and 12 leaves 5,7

and 11 as remainder?

a. 5 b.6. c.7. d.8

- 6 Comments
- for2 answer is 6..... !!!. 31 Jul '13.
- for2 the answer is 26. 23 Jul '13.

Ebook available of Nishit Sinha???

whats the difference between arun sharma and

Nishit Sinha book i already have been doing arun sharma and able to solve most of level 1 & 2 questions but somehow i am weak in some areas like permutations logs inequalities ie i need to strengthen my basics more so should i refer Nishit Sinha for this ??? if not then which other books can clear basics

- 1 Like

The number of natural numbers n such that "((n+1)^2)/ (n+7) " is an integer, is.. (I dont know the answer and not sure whether given ans is correct or not; so not giving correct one)

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