About this discussion

*This is a thread dedicated entirely to the problems faced by CAT Aspirants solving Nishit Sinha's Quant and LA/DI Book.* This thread will help CAt aspirants to understand the Basic concepts thoroughly for those who are using the book and wil...

Follow this discussion to get notified of latest updates.

Nice! Share it on Facebook so that your friends can join you here.

Order by:
New Posts

Page 3 of 13

notation : a2 => a raised to power 2.

a2=by+cz ; b2=cz+ax ; c2 = ax+by;

then [x/(a+x)] + [y/(b+y)] + [z/(c+z)] = ?

3 Comments

You can view the comments after answering or skipping this question.

If 29 goats graze a land in 7 days or 25 goats graze the same land in 9 days. How many goats will graze the same goat in 6 days. Please me know the solution.

4 Comments

You can view the comments after answering or skipping this question.

Your Gateway to Global Leadership

-Full time post graduate program in business

-Faculty from SDA Bocconi, Italy

-Dual Campus Mumbai and Milan

-2014 Avg. CTC 10 Lakh p.a - Merit based tuition waiver

Apply NowTo know our placement statistics download the brochure.

how many three digit natural numbers are there which when divided by 6 gives remainder 2 but when divided by 7 gives remainder 1 ??

- 7 Comments
- 21. 04 May '13.
- 21. 04 May '13.

in a scalene triangle sum of all sides can be at most 13 units. haw many triangles are possible?please share u r approach

6 Comments

Its "Do or Die" this time...

You can view the comments after answering or skipping this question.

In a recently concluded CBSE board exam,total of 6 lakh candidates appeared,40% of them are females and rest are males.Pass % of males is 75% and overall pass % is 70%.What is pass % of females?

3 Comments

You can view the comments after answering or skipping this question.

@incognito7 /from what i understand for vijays speed to be 0 it has to reduce 19 times .that is they gav to meet 19 times.

please solve this.. posting the link as i cant give the picture in the diagram. its geometry section, advanced level, q no 36

NO 36:

Two motorcyclists, Ajay and Vijay, start simultaneously from a point S on an oval track and drive around the track in the same direction, with speeds of 29 km/hr and 19 km/hr resp. Every time Ajay overtakes Vijay (anywhere on the track), both of them decrease their respective speeds by 1 km/hr. If the length of the track is 1 km, how many times do they meet at the starting point before Vijay comes to rest?

a) 2 b) 3 c) 5 d) 6

a) 2 b) 3 c) 5 d) 6

- 2. 23 Sep '13.

972282 Sayswhat is unitary method ???:nono:

unitary method is nothing but the method of carrying out a calculation to find the value of one unit to find the other one.

you can solve the above question by this method too:

formula:: {error/(true value - error value)} * 100

putting this in qs

50/(1000-50)*100 = required answer:)

See,

CP is for 1000 gms , so Sp also we have to calculate for 1000 gms

We know, SP of 950gms =x

therefore, unitary method, SP of 1000 gms = x*1000/950...

Now you can calculate the profit and tereby the profit%:)...

Is the answer correct?

Any problem, get back to me! :)

what is unitary method ???:nono:

hey regarding problem 31. I am not very sure. Just let me know if my ans is correct or not. This is the approach which I followed.

Profit of A first time = Rs. 1500.

SP of A =11500

B sells at 15% loss. CP of B=11500

SP of B = 11500 * .85 = 9775.

CP of A =9775.

Therefore profit made by A in the second transaction = (10000 -9775) = 225

Total profit = 1500+225 =1725

profit % = (1725/10000)*100 =17.25%

correct, thanks

See,

CP is for 1000 gms , so Sp also we have to calculate for 1000 gms

We know, SP of 950gms =x

therefore, unitary method, SP of 1000 gms = x*1000/950...

Now you can calculate the profit and tereby the profit%:)...

Is the answer correct?

Any problem, get back to me! :)

hey regarding problem 31. I am not very sure. Just let me know if my ans is correct or not. This is the approach which I followed.

Profit of A first time = Rs. 1500.

SP of A =11500

B sells at 15% loss. CP of B=11500

SP of B = 11500 * .85 = 9775.

CP of A =9775.

Therefore profit made by A in the second transaction = (10000 -9775) = 225

Total profit = 1500+225 =1725

profit % = (1725/10000)*100 =17.25%

ANSHER SHOULD BE 18.75%

sol;

let the list price be x.

so the retailer's cost price is 0.8x

and he sold at 0.95x

so % profit = {0.15x/0.80x}*100

=18.75%

could you plz help me with this ???

"SP 0f 1000 gms = x * 1000/950profit = 50 *x /950% profit = 5 5/19%:grin:

"

See,

CP is for 1000 gms , so Sp also we have to calculate for 1000 gms

We know, SP of 950gms =x

therefore, unitary method, SP of 1000 gms = x*1000/950...

Now you can calculate the profit and tereby the profit%:)...

Is the answer correct?

Any problem, get back to me!

972282 SaysNo answer is 'C'...

Let the list price be 'a'

CP(retailer) = SP (wholeseller) = a x 0.8

SP(retailer) = a x 0.95 = 38

therefore, a = 40

SP (retailer) = 38 and CP (retailer) = 40 x 0.8 =32

Profit for retailer = 38 - 32 = 6

so option C) is the answer

When you follow a discussion, you receive notifications about new posts and comments. You can unfollow a discussion anytime, or turn off notifications for it.

539 people follow this discussion.
7Comments »new comments