@Mr.Blue

Posted 30 Oct '09

Can Anybody give me a solution for this.
Q- in an examination, the maximum marks for each of the three papers is 50 each. the maximum marks for the fourth paper is 100. find the number of ways with which a student can score 60% in aggregate.
a) 330850 b)233551 c) 110551 d) 220800 e) none ...

Can Anybody give me a solution for this.

Q- in an examination, the maximum marks for each of the three papers is 50 each. the maximum marks for the fourth paper is 100. find the number of ways with which a student can score 60% in aggregate.

a) 330850 b)233551 c) 110551 d) 220800 e) none of these

Q- in an examination, the maximum marks for each of the three papers is 50 each. the maximum marks for the fourth paper is 100. find the number of ways with which a student can score 60% in aggregate.

a) 330850 b)233551 c) 110551 d) 220800 e) none of these

hi........:grin:

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@deepa_awasthi
12

Posted 20 Aug '08

Ya I'm aware of that formula for GP..thanks :)actually I was confused coz I assumed that there are 6 terms in GP including 4 GM....Any luck in solving Quant q 98 that I had posted earlier...
> MaskedMenace Says
>
> yeah...for a gp common ratio is term2/term1 ....nd it remain same through out d ...

Ya I'm aware of that formula for GP..thanks :)actually I was confused coz I assumed that there are 6 terms in GP including 4 GM....Any luck in solving Quant q 98 that I had posted earlier...

MaskedMenace Saysyeah...for a gp common ratio is term2/term1 ....nd it remain same through out d series...tht is wht i hav done....if not clear just revert

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Lava Kumar Dukanam
@MaskedMenace
4.1
k

Posted 19 Aug '08

> this is regd following q :
Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.
hey just one query....regd the way u calculated common ratio..
I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth te...

this is regd following q :

Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

hey just one query....regd the way u calculated common ratio..

I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth term as 128 and n =6we get common ratio as : 4....In your Method what I found dubious was that equaiton that you have formed....can you elaborate it a bit....coz assumin " x" is common ratio I thnk that equation can't be formed....

yeah...for a gp common ratio is term2/term1 ....nd it remain same through out d series...tht is wht i hav done....if not clear just revert

- 1 Like

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@deepa_awasthi
12

Posted 19 Aug '08

this is regd following q :
Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.
hey just one query....regd the way u calculated common ratio..
I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth term...

this is regd following q :

Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

hey just one query....regd the way u calculated common ratio..

I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth term as 128 and n =6we get common ratio as : 4....In your Method what I found dubious was that equaiton that you have formed....can you elaborate it a bit....coz assumin " x" is common ratio I thnk that equation can't be formed....

Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

hey just one query....regd the way u calculated common ratio..

I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth term as 128 and n =6we get common ratio as : 4....In your Method what I found dubious was that equaiton that you have formed....can you elaborate it a bit....coz assumin " x" is common ratio I thnk that equation can't be formed....

Just find the common ratio..n keep multiplying it ...

this is how it can b done...

1/8, _ , _ , _ , _ ,128

Now,128/x = 8x == >x =4 (common ratio)

so, 1/8,1/2,2,8,32,128 ....3rd gm is 8..

- 1 Like

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@deepa_awasthi
12

Posted 19 Aug '08

hello all,
quant Question no 98 :
*\------------------------------------------------------**
**Quantitative Question # 098*
*\------------------------------------------------------ *
*****Consider two distinct positive integers x and y having integer arithmetic, geometric and harm...

hello all,

quant Question no 98 :

**------------------------------------------------------**

**Quantitative Question # 098**

**------------------------------------------------------ **

**Consider two distinct positive integers x and y having integer arithmetic, geometric and harmonic means. The minimum value of x - y is **

**(1) 15 (2) 20 (3) 30 (4) 40 (5) 50**

And my logic for solving this is described in my post above...but as per that I'm not able to get an answer...

Need help .....

quant Question no 98 :

And my logic for solving this is described in my post above...but as per that I'm not able to get an answer...

Need help .....

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Lava Kumar Dukanam
@MaskedMenace
4.1
k

Posted 18 Aug '08

> Hello all,
I'm Deepa..
just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...
now goin by al...

Hello all,

I'm Deepa..

just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...

now goin by all this....lets consider even perfect squares like 4,16,36,64....and x&y; can be (2,2) ; (4,4) ; (-2,-2)....like wise and if we go by this method we can't get an answer....:...can sum1 sugg a way to solve it......

hoping for quick replies ;)..

i cldnt able to find q.no 98...please post tht ques...

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Lava Kumar Dukanam
@MaskedMenace
4.1
k

Posted 18 Aug '08

> Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.
I kno its a simple question but just cant find the answer!
Just find the common ratio..n keep multiplying it ...
this is how it can b done...
1/8, _ , _ , _ , _ ,128
Now,128/x = 8x ...

Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

I kno its a simple question but just cant find the answer!

Just find the common ratio..n keep multiplying it ...

this is how it can b done...

1/8, _ , _ , _ , _ ,128

Now,128/x = 8x == >x =4 (common ratio)

so, 1/8,1/2,2,8,32,128 ....3rd gm is 8..

Commenting on this post has been disabled.

@deepa_awasthi
12

Posted 18 Aug '08

Hello all,
I'm Deepa..
just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...
now goin by all ...

Hello all,

I'm Deepa..

just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...

now goin by all this....lets consider even perfect squares like 4,16,36,64....and x&y; can be (2,2) ; (4,4) ; (-2,-2)....like wise and if we go by this method we can't get an answer....:...can sum1 sugg a way to solve it......

hoping for quick replies ;)..

I'm Deepa..

just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...

now goin by all this....lets consider even perfect squares like 4,16,36,64....and x&y; can be (2,2) ; (4,4) ; (-2,-2)....like wise and if we go by this method we can't get an answer....:...can sum1 sugg a way to solve it......

hoping for quick replies ;)..

Commenting on this post has been disabled.

@arbit012

Posted 09 Aug '08

Bhaiyon Aur Behno,
Main QQAD subscribe karne ka param ichhuk hun. Meri iccha hai ki ek prashna pratidin pratah kal mere mail-box mein aaye. Maine subscribe karne ki link ki khoj ki lekin meri khoj asaphal rahi. Kya koi meri madad karna chahega?
Dhanyawad,
QQAD ka subscription pane ...

Bhaiyon Aur Behno,

Main QQAD subscribe karne ka param ichhuk hun. Meri iccha hai ki ek prashna pratidin pratah kal mere mail-box mein aaye. Maine subscribe karne ki link ki khoj ki lekin meri khoj asaphal rahi. Kya koi meri madad karna chahega?

Dhanyawad,

QQAD ka subscription pane ka param icchuk.

Main QQAD subscribe karne ka param ichhuk hun. Meri iccha hai ki ek prashna pratidin pratah kal mere mail-box mein aaye. Maine subscribe karne ki link ki khoj ki lekin meri khoj asaphal rahi. Kya koi meri madad karna chahega?

Dhanyawad,

QQAD ka subscription pane ka param icchuk.

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@Fibs

Posted 23 Jul '08

Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.
I kno its a simple question but just cant find the answer!

I kno its a simple question but just cant find the answer!

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@zion1729
807

Posted 11 Jul '08

*\------------------------------------------------------**
**Quantitative Question # 065*
*\------------------------------------------------------ *
*If all palindromes (positive integers which is unchanged if you reverse the order of its digits) are written in increasing order, what is ...

The palindromes in increasing order are

1

2

3

...

9

11

22

33

...

99

101

111

121

131

...

191

202

212

222

...

We see that the prime difference can be either 2 or 11 - hence the answer is (3)

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@avenger007

Posted 07 Jul '08

hei...I can't understand the concept of no: of steps taken in an escalator..plz help me wid dis,
(speed of a person/speed of escalator) = (no: of steps on moving escalator / no: of steps of the person when escalator is off)
cld any one plz explain the concept..?

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..i too got 20/3..

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Anupam Khanna
@anupam_khanna
339

Posted 03 Jul '06

> *Question 101: *
*At his normal speed, Shirish can travel 18 km downstream in a fast flowing stream in 9 hours less than what he takes to travel the same distance upstream. The downstream trip would take 1 hour less than what the upstream trip would take provided he doubles his rate of rowing...

Question 101:At his normal speed, Shirish can travel 18 km downstream in a fast flowing stream in 9 hours less than what he takes to travel the same distance upstream. The downstream trip would take 1 hour less than what the upstream trip would take provided he doubles his rate of rowing. What is the speed of the stream in km/hr?

(a) 20/3 (b) 8 (c) 33/4 (d) none of the foregoingI am getting speed of stream as either zero(0) or negative(-20/3).9=18/(x+v)-18/(x-v)and1=18/(2x+v)-18/(2x-v)where x and v are speeds of Sirish and stream, respectively.on calculating first one the relation is: x^2=v^2-4vand then putting in second and solving.Am i wrong somewhere??

yup... its comin out to be...20/3

:

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