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Quantitative questions a day 51 to 100 - The discussions

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  • Created by @Aarav
I'm starting a new thread as the discussions will happen on this new thread for next 50 questions and the sectional test :-) Happy solving :smiley:
Can Anybody give me a solution for this.
Q- in an examination, the maximum marks for each of the three papers is 50 each. the maximum marks for the fourth paper is 100. find the number of ways with which a student can score 60% in aggregate.

a) 330850 b)233551 c) 110551 d) 220800 e) none of these

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hi........:grin:
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Ya I'm aware of that formula for GP..thanks :)actually I was confused coz I assumed that there are 6 terms in GP including 4 GM....Any luck in solving Quant q 98 that I had posted earlier...
MaskedMenace Says
yeah...for a gp common ratio is term2/term1 ....nd it remain same through out d series...tht is wht i hav done....if not clear just revert
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this is regd following q :
Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.


hey just one query....regd the way u calculated common ratio..
I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth term as 128 and n =6we get common ratio as : 4....In your Method what I found dubious was that equaiton that you have formed....can you elaborate it a bit....coz assumin " x" is common ratio I thnk that equation can't be formed....


yeah...for a gp common ratio is term2/term1 ....nd it remain same through out d series...tht is wht i hav done....if not clear just revert
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this is regd following q :
Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.


hey just one query....regd the way u calculated common ratio..
I thnk it shuld be...calculated using nth term of GP formula..In that putting first term as 1/8 and nth term as 128 and n =6we get common ratio as : 4....In your Method what I found dubious was that equaiton that you have formed....can you elaborate it a bit....coz assumin " x" is common ratio I thnk that equation can't be formed....





Just find the common ratio..n keep multiplying it ...

this is how it can b done...

1/8, _ , _ , _ , _ ,128


Now,128/x = 8x == >x =4 (common ratio)

so, 1/8,1/2,2,8,32,128 ....3rd gm is 8..
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hello all,

quant Question no 98 :
------------------------------------------------------
Quantitative Question # 098
------------------------------------------------------

Consider two distinct positive integers x and y having integer arithmetic, geometric and harmonic means. The minimum value of x - y is

(1) 15 (2) 20 (3) 30 (4) 40 (5) 50



And my logic for solving this is described in my post above...but as per that I'm not able to get an answer...

Need help .....
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Hello all,

I'm Deepa..
just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...
now goin by all this....lets consider even perfect squares like 4,16,36,64....and x&y; can be (2,2) ; (4,4) ; (-2,-2)....like wise and if we go by this method we can't get an answer....:...can sum1 sugg a way to solve it......

hoping for quick replies ;)..

i cldnt able to find q.no 98...please post tht ques...
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Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

I kno its a simple question but just cant find the answer!

Just find the common ratio..n keep multiplying it ...

this is how it can b done...

1/8, _ , _ , _ , _ ,128


Now,128/x = 8x == >x =4 (common ratio)

so, 1/8,1/2,2,8,32,128 ....3rd gm is 8..
Commenting on this post has been disabled.
Hello all,

I'm Deepa..
just had this query regd the Quant Q 98 :It says AM,GM,HM all should be integral..so that means the no's x & y should be an even perfect square ...x & y can be both positive or both negative....coz otherwise we can't get an intergral square root...
now goin by all this....lets consider even perfect squares like 4,16,36,64....and x&y; can be (2,2) ; (4,4) ; (-2,-2)....like wise and if we go by this method we can't get an answer....:...can sum1 sugg a way to solve it......

hoping for quick replies ;)..
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Bhaiyon Aur Behno,

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Four Geometrical means are inserted between 1/8 and 128.find the 3rd Geometrical mean.

I kno its a simple question but just cant find the answer!
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------------------------------------------------------
Quantitative Question # 065
------------------------------------------------------

If all palindromes (positive integers which is unchanged if you reverse the order of its digits) are written in increasing order, what is the possible number of prime values can the difference between successive palindromes take?



(1) 0 (2) 1 (3) 2 (4) 3 (5) none of these

The palindromes in increasing order are

1
2
3
...
9
11
22
33
...
99
101
111
121
131
...
191
202
212
222
...

We see that the prime difference can be either 2 or 11 - hence the answer is (3)
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hei...I can't understand the concept of no: of steps taken in an escalator..plz help me wid dis,
(speed of a person/speed of escalator) = (no: of steps on moving escalator / no: of steps of the person when escalator is off)

cld any one plz explain the concept..?
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..i too got 20/3..
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Question 101:
At his normal speed, Shirish can travel 18 km downstream in a fast flowing stream in 9 hours less than what he takes to travel the same distance upstream. The downstream trip would take 1 hour less than what the upstream trip would take provided he doubles his rate of rowing. What is the speed of the stream in km/hr?

(a) 20/3 (b) 8 (c) 33/4 (d) none of the foregoing


I am getting speed of stream as either zero(0) or negative(-20/3).
9=18/(x+v)-18/(x-v)
and
1=18/(2x+v)-18/(2x-v)

where x and v are speeds of Sirish and stream, respectively.
on calculating first one the relation is: x^2=v^2-4v

and then putting in second and solving.
Am i wrong somewhere??

yup... its comin out to be...20/3
:
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