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Official Quant Thread for CAT 2012 [part 3]

  • Discussion in CAT
  • Created by @pkaman
raghav507
The Pahadi Mod @raghav507 51.5 k
http://www.pagalguy.com/forum/quantitative-questions-and-answers/82184-official-quant-thread-cat-2012-a.html
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kannabal
Bala V S @kannabal 82
> Can anyone help me with this question _lagaan is levied on the 60% of the cultivated land .the revenue department collected total of RS 384000 through the lagaan from the village of sukhaya ,sukhaiya a rich farmer paid only RS 480 as lagaan .the percentage of the total land of sukhaiya ove...
Can anyone help me with this question

lagaan is levied on the 60% of the cultivated land .the revenue department collected total of RS 384000 through the lagaan from the village of sukhaya ,sukhaiya a rich farmer paid only RS 480 as lagaan .the percentage of the total land of sukhaiya over the total taxable land of the village is:
a)0.15% b)15% c)0.125% d)none of these


Hi ..
is it 0.125% ?
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kannabal
Bala V S @kannabal 82
> nil1989 Says > > what are the last 2 digits of the nos 169^31? for finding the last 2 digits,always try and find out whether the number can be made to end with 1,which makes it very easy thereafter as final digit in this case will always be 1. In this case 169 if squared will end u...
nil1989 Says
what are the last 2 digits of the nos 169^31?



for finding the last 2 digits,always try and find out whether the number can be made to end with 1,which makes it very easy thereafter as final digit in this case will always be 1.
In this case 169 if squared will end up with number ending with 1 :
so (169^2)^29 = (...61)^29 [its enough to find out the last 2 digits)

therefore last 2 digits of the above power number = 51 (5 from 6 *9 = 54 )
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balajimaheshwar
@balajimaheshwar
Can anyone help me with this question _lagaan is levied on the 60% of the cultivated land .the revenue department collected total of RS 384000 through the lagaan from the village of sukhaya ,sukhaiya a rich farmer paid only RS 480 as lagaan .the percentage of the total land of sukhaiya over ...
Can anyone help me with this question

lagaan is levied on the 60% of the cultivated land .the revenue department collected total of RS 384000 through the lagaan from the village of sukhaya ,sukhaiya a rich farmer paid only RS 480 as lagaan .the percentage of the total land of sukhaiya over the total taxable land of the village is:
a)0.15% b)15% c)0.125% d)none of these
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sam05
Soham @sam05 3.8 k
> ananthraghavalu Says > > page not found??? also still 5 more pages we can spend in this thread itself!! *are sorry use the link of Aizen.ya i know u can use.but ek jagah pe discussion hota he to its good for everyone i guess*
ananthraghavalu Says
page not found??? also still 5 more pages we can spend in this thread itself!!

are sorry use the link of Aizen.ya i know u can use.but ek jagah pe discussion hota he to its good for everyone i guess
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ananthraghavalu
Ananth R @ananthraghavalu 74
page not found??? also still 5 more pages we can spend in this thread itself!! > %29"]http://www.pagalguy.com/forum/quanti...ml#post3509369 (Official Quant Thread for CAT 2012 ) bhai please continue here.request
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sam05
Soham @sam05 3.8 k
> mba4mheart Says > > my take is also 0 :: )"]http://www.pagalguy.com/forum/quanti...ml#post3509369 (Official Quant Thread for CAT 2012 ) bhai please continue here.request
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mba4mheart
NAKUL CHOPRA @mba4mheart 551
> Find the remainder when 1^5+2^5+3^5+... ...+100^5 is divided by 4? (explain plz) my take is also 0 ::
Find the remainder when
1^5+2^5+3^5+... ...+100^5 is
divided by 4? (explain plz)


my take is also 0
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Aizen
Aizen . @Aizen 4.5 k
Please continue your discussions here. http://www.pagalguy.com/forum/quantitative-questions-and-answers/82184-official-quant-thread-cat-2012-a.html#post3509369
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ananthraghavalu
Ananth R @ananthraghavalu 74
bro, in the binomial expansion of (2+1)^1024= 2^1024*1^0+2^1023*1^1.....2^0*1^1024 -1 thus the highest term will be 2^1024-1=2^1023.. am i wrong anywhere?? > (3^1024-1)can be written as (2+1)^1024-1 which means in the expansion of (2+1)^1024 last term will be 1 nad will be cancelled by...
bro, in the binomial expansion of (2+1)^1024= 2^1024*1^0+2^1023*1^1.....2^0*1^1024 -1
thus the highest term will be 2^1024-1=2^1023..
am i wrong anywhere??

(3^1024-1)can be written as (2+1)^1024-1 which means in the expansion of (2+1)^1024 last term will be 1 nad will be cancelled by -1....ao the whole expansion will be C(1024,0)2^1024+C(1024,1)2^1023+.......C(1024,1)2^1
LAST TERM IS 1024*2=2048 IE 2^11=2^X
HENCE x=11.
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singhjaskiran81
jaskiran singh @singhjaskiran81 49
it is 12.. break the above into a^2 - b^2 form.. it will reduce like (3^512 +1) (3^512-1) .. at last (3^2-1)(3^2+1) will be left..
it is 12.. break the above into a^2 - b^2 form.. it will reduce like (3^512 +1) (3^512-1) .. at last (3^2-1)(3^2+1) will be left..
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Aizen
Aizen . @Aizen 4.5 k
> Q) If the graph of the function f(x)= (a^x)-1/x^n*((a^x)+1) is symmetric about y-axis then what is the value of n? ans -1/3 please explain TIA Symmetric about Y axis So ,this is an even function. so use f(x)=f(-x) to find the value of n
Q) If the graph of the function f(x)= (a^x)-1/x^n*((a^x)+1) is symmetric about y-axis then what is the value of n?

ans -1/3

please explain

TIA


Symmetric about Y axis So ,this is an even function.
so use f(x)=f(-x) to find the value of n
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mailtoankit
ankit gupta @mailtoankit 4.4 k
Q) If the graph of the function f(x)= (a^x)-1/x^n*((a^x)+1) is symmetric about y-axis then what is the value of n? ans -1/3 please explain TIA
Q) If the graph of the function f(x)= (a^x)-1/x^n*((a^x)+1) is symmetric about y-axis then what is the value of n?

ans -1/3

please explain

TIA
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gudda1122
shubham sharma @gudda1122 10.6 k
> both are same bro,10/(3)^1/2((3^1/2)+1) = 10/(3 + rt(3)) :) *My mistake sorry brother... kindly share your approach.... and please will someone explain on which thread we are supposed to post question???????only open thread after this one is closed*

both are same bro,10/(3)^1/2((3^1/2)+1) = 10/(3 + rt(3)) :)

My mistake sorry brother...
kindly share your approach....

and please will someone explain on which thread we are supposed to post question???????only open thread after this one is closed
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ziddiarmaan
kya karoge Jaan Ke ..:) @ziddiarmaan 1.7 k
> thanks fapsian19... here's another 1... *1!+2*2!+....+12*12! when divided by 13 leaves remainder?? 12 remainder ... but i find it manually :smiley: no gud ways :smiley:
thanks fapsian19... here's another 1...
*1!+2*2!+....+12*12! when divided by 13 leaves remainder??

12 remainder ... but i find it manually no gud ways
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