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Deepak Pandey
@deepak_pgi
5.0
k

Please continue here:
http://www.pagalguy.com/forum/quantitative-questions-and-answers/74749-geometry-for-cat-2012-a.html#post3053072

Bhavya Mehta
@bhavya1421
45

> Hi Guys,
Geometry, Algebra and Number system form the major chunk of our QA section for CAT.
Proficiency in these three sections would definitely boost our Quants scores.
Contents of Geometry
1\. Plane Geometry - Basics and Triangles
2\. Polygons and Quadrilaterals
3\. C...

Hi Guys,

Geometry, Algebra and Number system form the major chunk of our QA section for CAT.

Proficiency in these three sections would definitely boost our Quants scores.

Contents of Geometry

1. Plane Geometry - Basics and Triangles

2. Polygons and Quadrilaterals

3. Circle

4. Mensuration

5. Trignometry

6. coordinate Geome

i tried to dowmload it..but was nt able to do so:-(...help..my email id is bhavyamehta1421@gmail.com

regards

bhavya

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Amity Business School, Lucknow Invites Applications for MBA 2014

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Applications Open!

Bhavya Mehta
@bhavya1421
45

same here dude..were u able to do it later..plz reply..regards bhavya

same here dude..were u able to do it later..plz reply..regards bhavya

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Ashish
@mbaashish5
457

> vibhormittal360 Says
>
> There are 3 balls in a plane touching each other equally and above it another ball placed touching all the balls equally, we have the find the distance of the bottom of the above ball to the ground...how can this problem be solved???
Three balls touching each ot...

vibhormittal360 SaysThere are 3 balls in a plane touching each other equally and above it another ball placed touching all the balls equally, we have the find the distance of the bottom of the above ball to the ground...how can this problem be solved???

Three balls touching each other can placed like

:-(:-(

:-(

consider these connected to each other, And a ball is above in the center,

now the ball center from earth above earth is radius of any ball.

now the centers of 3 balls makes the equilateral triangle.

try to imagine a ball above it...

if you keep a ball above it

it will take a shape like pyramid. base is Equi. triangle and top is in middle

if we draw a perpendicular on the triangle it will meet centroid. so centroid is 2/3 of perpendicular inside the triangle.

Now you need to again apply one time for hight.

than hight+ radius is your answer.

I hope I am pretty clear on that.

Thanks

Ashish

- 1 Like

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@vibhormittal360

There are 3 balls in a plane touching each other equally and above it another ball placed touching all the balls equally, we have the find the distance of the bottom of the above ball to the ground...how can this problem be solved???

There are 3 balls in a plane touching each other equally and above it another ball placed touching all the balls equally, we have the find the distance of the bottom of the above ball to the ground...how can this problem be solved???

Commenting on this post has been disabled.

Sourav Pal
@sunil89
126

Guys which book is best for Geometry and trigo preparation? Please help me as I am going to start my prep.

Guys which book is best for Geometry and trigo preparation? Please help me as I am going to start my prep.

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Sagar Pattnaik
@Ricky25
1.5
k

> Hi Puys,
I have a geometry Q which I'm stuck with. Please post the solution if u are able to solve it.
*Q)* In a cyclic quadrilateral ABCD, AB = 2, BC = 3, CD = 4 and AD = 5. What is the ratio of the lengths of the diagonals?
a) 7:11
b) 11:13
c) 10:11
d) 13:15
e) 15:7
Than...

Hi Puys,

I have a geometry Q which I'm stuck with. Please post the solution if u are able to solve it.Q)In a cyclic quadrilateral ABCD, AB = 2, BC = 3, CD = 4 and AD = 5. What is the ratio of the lengths of the diagonals?

a) 7:11

b) 11:13

c) 10:11

d) 13:15

e) 15:7

Thanks in advance,

Sandeep

In a cyclic quadrilateral ABCD the ratio of the diagonals equals the ratio of the sums of products of the sides that share the diagonals' end points. In other words,

(1) AC / BD = (ABAD + BCCD) / (ABBC + ADCD).

Triangles PAD and PBC are similar, so that

PA/PB = AD/BC = PD/PC,

which can be also written as

(2) ABAD/PA = ABBC/PB, and

BCCD/PC = ADCD/PD, In the same manner, the similarity of triangles PAB and PDC implies

(3) ABAD/PA = ADCD/PD.

which shows that four expressions

(4) ABAD/PA, ABBC/PB, BCCD/PC, and ADCD/PD are all equal. (1) follows by combining the first and the thrid terms and also the second and the fourth.

- 6 Likes

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Sandeep Bellapukonda
@CAT_RACER
14

Hi Puys,
I have a geometry Q which I'm stuck with. Please post the solution if u are able to solve it.
*Q)* In a cyclic quadrilateral ABCD, AB = 2, BC = 3, CD = 4 and AD = 5. What is the ratio of the lengths of the diagonals?
a) 7:11
b) 11:13
c) 10:11
d) 13:15
e) 15:7
Thanks...

Hi Puys,

I have a geometry Q which I'm stuck with. Please post the solution if u are able to solve it.

**Q)** In a cyclic quadrilateral ABCD, AB = 2, BC = 3, CD = 4 and AD = 5. What is the ratio of the lengths of the diagonals?

a) 7:11

b) 11:13

c) 10:11

d) 13:15

e) 15:7

Thanks in advance,

Sandeep

I have a geometry Q which I'm stuck with. Please post the solution if u are able to solve it.

a) 7:11

b) 11:13

c) 10:11

d) 13:15

e) 15:7

Thanks in advance,

Sandeep

- 1 Like

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Alok Kumar
@alokkhg
74

sorry the data was missing
Q is the point of intersection of AC and DB inside the circle

sorry the data was missing

Q is the point of intersection of AC and DB inside the circle

Q is the point of intersection of AC and DB inside the circle

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darshan GATTANI
@dagattani
80

wat is point Q dude ??? i mean how is AQB forming...data missing i guess

wat is point Q dude ??? i mean how is AQB forming...data missing i guess

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Alok Kumar
@alokkhg
74

puys i have a question in which i am stuck :help
C and D are points on the circle with diameter AB such that (angle AQB) =2*(angle COD), where O the center of the circle. Q is the point of intersection of AC and DB inside the circle.The tangents at C and D meet at P. The circle has radius 1....

puys i have a question in which i am stuck :help

C and D are points on the circle with diameter AB such that (angle AQB) =2*(angle COD), where O the center of the circle. Q is the point of intersection of AC and DB inside the circle.The tangents at C and D meet at P. The circle has radius 1. The distance of P from its center is:

(a) (sqrt2)/3

(b) 2/(sqrt3)

(c) 3/(sqrt2)

(d) 1

C and D are points on the circle with diameter AB such that (angle AQB) =2*(angle COD), where O the center of the circle. Q is the point of intersection of AC and DB inside the circle.The tangents at C and D meet at P. The circle has radius 1. The distance of P from its center is:

(a) (sqrt2)/3

(b) 2/(sqrt3)

(c) 3/(sqrt2)

(d) 1

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Ruchika
@ceoruchika
32

OK...i am losing the track here...in the question,it is not specified that he has to cover all the cities.Is that we are taking into account while solving??
> From top city,3 routes are possible
Since there are 3 edges leading from each city and also the figure is perfectly symmetrica...

OK...i am losing the track here...in the question,it is not specified that he has to cover all the cities.Is that we are taking into account while solving??

From top city,3 routes are possible

Since there are 3 edges leading from each city and also the figure is perfectly symmetrical, these 3 routes are possible from each edge.

So,total number of routes = 4 * 3 = 12.

ps : one more ceo from Delhi

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/* *\
@naga25french
81.7
k

> Four cities are connected by a road network as shown in the figure. In how many ways can you start from any city and come back to it without traveling on the same road more than once
10,12,14,15
I am getting 13 as the answer..that too by calculating manually all the routes.Is there any shor...

Four cities are connected by a road network as shown in the figure. In how many ways can you start from any city and come back to it without traveling on the same road more than once

10,12,14,15

I am getting 13 as the answer..that too by calculating manually all the routes.Is there any shortcut for such questions??

Image is attached.

From top city,3 routes are possible

Since there are 3 edges leading from each city and also the figure is perfectly symmetrical, these 3 routes are possible from each edge.

So,total number of routes = 4 * 3 = 12.

ps : one more ceo from Delhi

Commenting on this post has been disabled.

Ruchika
@ceoruchika
32

> If x, y, z are the angles of a triangle where x, y, z are integers, what is the number if values that x-y-z can take?
1\. 90
2\. 355
3\. 178
4\. 177
Please provide me with a solution.....
Quote:Solution I found on PG :
Originally Posted by *quantphobic* [image]
_If x...

If x, y, z are the angles of a triangle where x, y, z are integers, what is the number if values that x-y-z can take?

1. 90

2. 355

3. 178

4. 177

Please provide me with a solution.....

Quote:Solution I found on PG :

Originally Posted by

x-y-z = 180-2(y+z)

y+z -> 2 to 179

So, 178 values...

- 2 Likes

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Ruchika
@ceoruchika
32

Four cities are connected by a road network as shown in the figure. In how many ways can you start from any city and come back to it without traveling on the same road more than once
10,12,14,15
I am getting 13 as the answer..that too by calculating manually all the routes.Is there any ...

Four cities are connected by a road network as shown in the figure. In how many ways can you start from any city and come back to it without traveling on the same road more than once

10,12,14,15

I am getting 13 as the answer..that too by calculating manually all the routes.Is there any shortcut for such questions??

Image is attached.

10,12,14,15

I am getting 13 as the answer..that too by calculating manually all the routes.Is there any shortcut for such questions??

Image is attached.

Commenting on this post has been disabled.

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