Is ab an even number ?
I. a is divisible by 3.
II. (b+1) is divisible by 4.
The correct answer it says is II, how??
I think the correct answer is not II. it shud be III
a is divisible by 3, so it is an odd number.
(b+1) is divisible by 4,so (b+1) is a even number and hence b an odd number
As both a and b are odd numbers their product can never be an even number. therefore ab is an odd number. i.e the question can be solved using both I and II
If n is a natural number, is n ! < ^x ?
I. n is an even number.
II. x > n
answer III, how?
case 1)Taking n as 1 and x as 10, we get 1=1
case 2)with n as 2 and x as 10 , we get 2 < 1.5^10
case 3)with n as 2 and x as 1 , we get 2 > 1.5
so case 2 results r consistent(the other combinations do not result in a consistent 'yes' or 'no')
thus the answer is III..it can be answered using both the statements together.
If x^a = y^b > z^c, is x = y > z?
I. a = b > c
II. a = b = c
The answer is III, how??