webby

@webby

webby
vaibhav @webby
how many negative integer sol exists for x^2-y^2 =400? If x is a real no then what is the no of solutions for the eq: ((x^4-16)(x^2-4))^1/2? the set of all real nos x for which x^2-|x+2|+x >0
webby
vaibhav @webby

The OA is 2..i don't know how to solve these ques dats why I have posted..

webby
vaibhav @webby
how many negative integer sol exists for x^2-y^2 =400? If x is a real no then what is the no of solutions for the eq: ((x^4-16)(x^2-4))^1/2? the set of all real nos x for which x^2-|x+2|+x >0
webby
vaibhav @webby
how many negative integer sol exists for x^2-y^2 =400? If x is a real no then what is the no of solutions for the eq: ((x^4-16)(x^2-4))^1/2? the set of all real nos x for which x^2-|x+2|+x >0
webby
vaibhav @webby

but how to solve such ques?

how many negative integer sol exists for x^2-y^2 =400? If x is a real no then what is the no of solutions for the eq: ((x^4-16)(x^2-4))^1/2? the set of all real nos x for which x^2-|x+2|+x >0

how many negative integer sol exists for x^2-y^2 =400?

If x is a real no then what is the no of solutions for the eq:

((x^4-16)(x^2-4))^1/2?

the set of all real nos x for which x^2-|x+2|+x >0

  • 1 Like   20Comments
  • @saphira1 I think ur 3rd answer is wrong it can not be -i.... 29 Jul.
  • i think the answer for third one should be .. from 2 to i.... 29 Jul.
  20 Comments
saphira1
swati garg @saphira1 34

Answer1 - 4 ways (-101, -99), (-52,-48) (-29, -21) and (-25, -15).

Answer2 - infinite solutions.

Answer 3 (-inf, -rt2) (rt2, inf)

nitinknandan
nitin nandan @nitinknandan 3

@saphira1 exactly my point, if u see the number of positive integral solutions will also be the same

saphira1
swati garg @saphira1 34

yeah. That's how I got it too. Only takeaway from the word "negative" is that |x|>|y|.

Anirban_kar
Anirban Kar @Anirban_kar 14

Yes, @swati  The total answers will be 8 only. We just have to take the even factors that make up 400 only. Total factors = 15, of which (5, 80), (25,16), & (1,400) will be taken off. So, it seems that the answer is 15 -6 = 9. But, again (20,20) will have only 1 solution instead of 2. So, 8 is the final answer. Thanks for the tips.

mack01
mayank asd @mack01 48

@saphira1 I think ur 3rd answer is wrong it can not be -inf to -rt2?

asaktidev
_rininir_ _dev_ @asaktidev 1

i think the answer for third one should be .. from 2 to infinity

webby
vaibhav @webby
Here are few ques... A speaks truth in 60% cases and B in 70% cases. Wat is the prob that they will do the same thng while describing a single event. If they both lie, they tell the same thing? A nd B toss coin alternatively till one of them gets a head. If A starts find the prob that B will wi...
webby
vaibhav @webby

third one is 4/13..plz explain other two also 2 & 3

Here are few ques... A speaks truth in 60% cases and B in 70% cases. Wat is the prob that they will do the same thng while describing a single event. If they both lie, they tell the same thing? A nd B toss coin alternatively till one of them gets a head. If A starts find the prob that B will wi...

Here are few ques...

A speaks truth in 60% cases and B in 70% cases. Wat is the prob that they will do the same thng while describing a single event. If they both lie, they tell the same thing?

A nd B toss coin alternatively till one of them gets a head. If A starts find the prob that B will win the game.

the prob of picking a spade or an ace not of spade from a pack of 52 cards is?

  • 9Comments
  • third one is 4/13..plz explain other two also 2 & 3. 27 Jul.
  • @webby the second one is P(B winning)= P(A gets tails)*.... 28 Jul.
  9 Comments
webby
vaibhav @webby 34

third one is 4/13..plz explain other two also 2 & 3

allok
alok k @allok 2

@webby the second one is 

P(B winning)= P(A gets tails)*P(B gets head) + P(A gets tails)*P(B gets tails)*P(A gets tails)*P(B gets head) +P(A gets tails)*P(B gets tails)*P(A gets tails)*P(B gets tails)*P(A gets tails)*P(B gets head) +. so on upto infinity

the probability of P(A gets tails)= P(B gets head) = P(B gets tails) = 1/2

So P(B winning) is a GP with infinite terms with first term a = 1/4 and r= 1/4

So P(B winning) =a/(1-r) = 1/4/(1-1/4)=1/3

For the 3rd one in a pack of cards there are 13 spades + 3 ace except the ace of spades

So we have probability =16/52 =4/13

how to find the 30th term of this series 1,3,6,10,15... plz explain

how to find the 30th term of this series

1,3,6,10,15...

plz explain

  • 2 Likes   6Comments
  • 465. 25 Jul.
webby
vaibhav @webby
In a group of newly married couples, 10% of husbands and 45% of wives are unemployed. What is the probability that a person selected at random is employed?
In a group of newly married couples, 10% of husbands and 45% of wives are unemployed. What is the probability that a person selected at random is employed?

In a group of newly married couples, 10% of husbands and 45% of wives are unemployed. What is the probability that a person selected at random is employed?

  • 10Comments
  • 29/100. 25 Jul.
  • 29/40. 25 Jul.
webby
vaibhav @webby
one man can do as much wrk in one day as a woman can do in 2 days. A child does the one third the work in a day as a woman. If an estate owner hires 39 pairs of hands, men , women , children in the ratio 6:5:2 and pays them in all Rs 1113 at the end of the day's work. What mst be the daily wages ...