upudit0

@upudit0

  • udit pande
  • 1,640 karma
upudit0
udit pande @upudit0
What is the maximum possible number of intersection points between three lines, five circles and seven triangles? *OPTIONS* 1)430 2)433 3)436 4)333 5)336 how i approached when only lines =3c2 =3only circles=5c2*2 =20only triangles=7c2*6 =126line and circle =3c1*5c1*2=30line and triang...
upudit0
udit pande @upudit0
@Dexian  we need max so we don't cosinder that and we have counted it earlier
meenu05
meenakshi sundareswaran @meenu05
please solve the question number 18
upudit0
udit pande @upudit0

in ODC  /_odc=60 (equilateral )
in AOD /_aod=90 (AD=4sqrt2 as DAB is right angle formed in semicircle )

/_aoc=150  now oa=oc=4  apply cosine rule to get AC

What is the maximum possible number of intersection points between three lines, five circles and seven triangles?

OPTIONS

1)430

2)433

3)436

4)333

5)336


how i approached when only lines =3c2 =3only circles=5c2*2 =20only triangles=7c2*6 =126line and circle =3c1*5c1*2=30line and triangle=3c1*7c1*2=42triangle and circle =7c1*5c1*6=2103+20+126+30+42+210=431


kahan galat kiya ??


  • 5 Comments
  • @Dexian 3 wala point maine bhi socha tha but kitna hoga 3.... 26 Apr '13.
  • i think u have considered only wala cases and 2 waala cas.... 26 Apr '13.
AvishekAdhvaryu
Avishek Adhvaryu @AvishekAdhvaryu 341
@Dexian 3 wala point maine bhi socha tha but kitna hoga 3 wala points? 
2/3/5?
Dexian
Ashutosh Verma @Dexian 3,864
i think u have considered only wala cases and 2 waala case... 3 wala cases bhi hoga jab all 3 meet.. IMO

my cat 2012 question


(1+x+x^2)^10 =a0+a1x+a2x^2+.......+a20x^20

find

(a0+a2+a4........+a20 )/(a1+a3+a5+......+a19)

1)2^10+1/(2^10-1)

2) 2^10-1/(2^10+1)

3) 3^10+1/(3^10-1)

4) 3^10-1/(3^10+1)


  • 7 Comments
  • @anytomdickandhary Great solution Sir...... 24 Apr '13.
  • put x=1 to get a0+a1+a2+......+a20 = (1+1+1)10 = 310.... 24 Apr '13.
anytomdickandhary
anytomdickandhary aytomdickandhary @anytomdickandhary 6,591
put x=1 to get

a0+a1+a2+......+a20 = (1+1+1)10 = 310........................ (i)

Put x = -1 to get

a0-a1+a2-......-a19+a20 = (1-1+1)10 = 110 ...................... (ii)

Add (i) and (ii) to get

2*(a0+a2+a6+......+a20) = 310 + 1.

Subtract (ii) from (i) to get

2*(a1+a3+a5+......+a19) = 310 - 1.

Divide the results to get

Tusharrr
Tushar Gautam @Tusharrr
The quadratic polynomial f(x)=x^2+4x+52 has a complex root z. What is the value of N(z)?
Tusharrr
Tushar Gautam @Tusharrr
It is given that the cubic polynomial f(x) has real coefficients, and f(x)=0 has a complex root 15−14i. If the sum of all the complex, non-real roots of f(x)=0 can be written as a+bi, what is the value of a+b?
upudit0
udit pande @upudit0
I am from Lucknow (uttar pradesh) and have my grad exam on 8 may but got gd/pi letter for 10th may on 9:30 will i be able to reach at 10th on time at mumbai i have never travlled to mumbai before ?
upudit0
udit pande @upudit0
I am from Lucknow (uttar pradesh) and have my grad exam on 8 may but got gd/pi letter for 10th may on 9:30 will i be able to reach at 10th on time at mumbai i have never travlled to mumbai before ?
upudit0
udit pande @upudit0

and do i have to reach at 9:30 sharp or can't it be later ??

upudit0
udit pande @upudit0
I am from Lucknow (uttar pradesh) and have my grad exam on 8 may but got gd/pi letter for 10th may on 9:30 will i be able to reach at 10th on time at mumbai i have never travlled to mumbai before ?