ujjumba Saysis ans is 128??
saurav_chetry SaysHi Puys please help me out in finding the remainder of 2^133/133. Please inform me if there is any approach pertaining to the problems where the divisor and the power are same?
there is a shortcut but works only if divisor is prime number.
Fermet's theorem: If p is prime number then n^p%p would always be n.
So here answer would be 2.
its 122976
sum of AP ,last term 997 ,1st term 101, D = 4
Suja
ABCLIKS SaysCan u plz give the approach...?
What is the sum of all the three digit numbers which leave the
remainder 1 when divided by 4?
(a)123525 (b)122976 (c)112996 (d)100000
victory2010 SaysIf a+b+c=3 and a(^2)+b(^2)+c(^2)=5 and a(^3)+b(^3)+c(^3)=7 what is a(^4)+b(^4)+c(^4) ?
topper@IITK SaysThere are 30 people and 3 clubs M, S, and Z in a company. 10 people joined M, 12 people joined S and 5 people joined Z. If the members of M did not join any other club, at most, how many people of the company did not join any club?
4-10000! = (100!)K P, where P and K are integers. What can be the
maximum value of K?
yaar K*P=10000x9999x9998x.......102x101....
obviously K max is 10000x9999x9998x.......102...!!!!