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Hey, all who like to write on Quant should know about this.

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Amit is standing on vertex A of triangle ABC, with AB = 3, BC = 5, and CA = 4. Amit walks according to the following plan: He moves along the altitude-to-the-hypotenuse until he reaches the hypotenuse. He has now cut the original triangle into two triangles; he now walks along the altitude to the hypotenuse of the larger one. He repeats this process forever. What is the total distance that Amit walks?

(a) 48/25 (b) 12/5 (c) 12 (d) 15

- 4 Comments
- h=2.4...and h'=1.92... r=4/5.. sum=2.4/(1-4/5)=2.4*5=12. 27 Aug '14.
- @happy3475 ...sir can you please go a bit deeper...:(. 27 Aug '14.