NeTworK

@NeTworK

its always better to go for a licenesed antivirus , you can pass a year without the tension of any viruses , kaspersky is a great antivirus, i buy it every year, using it from last 3 years, no problem ever ::
its always better to go for a licenesed antivirus , you can pass a year without the tension of any viruses , kaspersky is a great antivirus, i buy it every year, using it from last 3 years, no problem ever
please solve this what is x if ::
please solve this

what is x if

Attachments
> It can have multiple answers it is quite clear that S = 9 m = 1 R = 8 O=0 e+1 = n now e can be 3/4/5;n ==> 4/5/6 thankyou brother:D
It can have multiple answers
it is quite clear that
S = 9
m = 1
R = 8
O=0
e+1 = n
now e can be 3/4/5;n ==> 4/5/6


thankyou brother:D
Each alphabet stands for a digit. Try and determine which letter stands for which digit. Please explain also
Each alphabet stands for a digit. Try and determine which letter stands for which digit.

Please explain also
Attachments
*YES ITS 900 ALL OF YOU ARE CORRECT* :: *and thanks for solving it for me*
YES ITS 900 ALL OF YOU ARE CORRECT

and thanks for solving it for me
Can some1 please solve this with approach Q : What is the least square number which is divisble by 3,5,6 and 9 ? ::
Can some1 please solve this with approach

Q : What is the least square number which is divisble by 3,5,6 and 9 ?
> 9456 1087 \------ 10543 check your answer , answer almost there and please post the approach also ::
9456
1087
------
10543


check your answer , answer almost there

and please post the approach also
> my take 4 2*2.....(203 times) %7 (2*2*2) % 7 is 1 so 2*2*2........up to 201 digit remainder is 1 2*2% 7 = 4 correct :: thankyou brother
my take 4

2*2.....(203 times) %7

(2*2*2) % 7 is 1

so 2*2*2........up to 201 digit remainder is 1

2*2% 7 = 4


correct
thankyou brother
Please explain the method behind the following question :: Find the remainder when (51)^203 is divided by 7 a) 4 b) 2 c) 1 d) 6
Please explain the method behind the following question

Find the remainder when (51)^203 is divided by 7

a) 4
b) 2
c) 1
d) 6
> UtsavGambhir Says > > It would be 31 and "y" in that case would have 9 cards. If "y" gives "x" 1 card then the count with both would be 8 and 32. When "x" gives 1 card to "y", the count would be 10 and 30. explanation to this would be highly appreciated ::
UtsavGambhir Says
It would be 31 and "y" in that case would have 9 cards. If "y" gives "x" 1 card then the count with both would be 8 and 32. When "x" gives 1 card to "y", the count would be 10 and 30.


explanation to this would be highly appreciated