Please help me with the following questions:
1. Joshua and Jose work at an auto repair center with 4 other workers. For a survey on healthcare insurance, 2 of the 6 workers are randomly chosen to beinterviewed. What is the probability that Joshua and Jose will be chosen?
A.1/15 B.1/12 C.1/9 D.1/6 E.1/3
2. The sum of first 50 positive even integers is 2550. What is the sum of even intergers from 102 to 200 inclusive?
A.5100 B.7550 C.10100 D.15500 E.20100
3. Is the hundredth digit of decimal d greater than 7?
i. The tenths digit of 10d is 7
ii. The thousandths digit of d/10 is 7
Hey.. can someone plz help me with this problem? Thanks a lot!
If n denotes a number to the left of 0 on the number line such that the square of n is less than 1/100, then the reciprocal of n must be
(1) less than -10
(2) between -1 and -1/10
(3) between -1/10 and 0
(4) between 0 and 1/10
(5) greater than 10
My Take: B
Here goes my solution!
Now the number of ways 3 positions can be taken by 9 people is 9 * 8 * 7
So, to find the peobability of atleast two positions going to the Triplets we need to find the probapility as:
Required Probability = Probability of 2 position going to triplets + Probability of all three position going to triplets
ie : P = P(2) + P(3)
Now P(2) = Triplets(1st & Second pos) + Triplets(Second & 3rd pos) + Triplets(1st & 3rd pos)
Therefire, P(2) =
=> p(2) = 108/(9 * 8 * 7)
Again, P(3) = (3 * 2 * 1) / (9 * 8 * 7)
So, P = 114/(9 * 8 * 7)
=> P = 19/84
You can also get the same result by suptracting Probability of none of them getting Medal and probability of only one of them getting medal from 1
i.e: P = 1 -
I am getiing d as answer can u check it please
n(AUBUC)= n(A)+n(B)+n(C)-((nA@B)+(nA@BC)+(nC@B))+(nA@B@C) where @ denotes intersection
using this we get the answer of ((nA@B)+(nA@BC)+(nC@B)) as 55 and substracting the 30 (10+10+10) from it as we need to find only the numbers of customers who purchase 2 of the items hence 25%
also the venn diagram gives the same result...