# @k_himanshu

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###### CATOfficial Quant Thread for CAT 2011 [Part 3]
meversusme Says
Definately something wrong with the options : getting 400/9......

sorry for the misspelling of the options bro.
The option was 44(4/9)

:D
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###### CATOfficial Quant Thread for CAT 2011 [Part 3]

Yes, the options are correct. It is from Time Sectional test.

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###### CATOfficial Quant Thread for CAT 2011 [Part 3]

Sachin, Saurav and Rahul enter into a partnership with capitals of 18000, 24000 and 48000. Saurav, apart from his share of profit, receives a certain percentage of the profit for managing the business. Sachin' s share in the profit is 30000. Find the percentage of the profit that Rahul receives if the total profit is 180000.
a) 444/9%
b) 361/3%
c) 531/3%
d) 345/9%

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###### CATOfficial Quant Thread for CAT 2011 [Part 3]
Hey u all puys,plz solve this ques as it makes a lot of puzzle 2 me....
Q:-the no of terms in an AP is odd.if the sum of all terms is 45 and the no of terms is 4 more than tha middle term,find the middle term-
1.9
2.4
3.6
4.5

(n-1)*Middle Term = 45- Middle Term
so, Middle term = 45/n

now n=Middle term(m) +4
i.e. m(m+4) = 45
5(5+4) = 45

hence m = 5
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###### GMATUniversity of Georgia - Terry College of Business

can you please tell what are the MBA programs that are available at Terry college of business?

Himanshu

###### CATOfficial Quant Thread for CAT 2011 [Part 3]

Is it 145 ?

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###### CATOfficial Quant Thread for CAT 2011 [Part 3]
x - 7xy + 12y - 4 = 0
D should be a perfect sq

49y - 48y + 16 should be a perfect sq
y + 16 = p
(p - y)(p + y) = 16 = 2*8
p = 5, y = 3

So, only one possible value.

Hi chill Bhai,
I got your solution man however can you pls explain why D should have to be a perfect sq ?

Thanks,
Himanshu
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###### CATOfficial Quant Thread for CAT 2011 [Part 3]

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###### CATOfficial Quant Thread for CAT 2011 [Part 3]
what is the last non zero digit for the sum
84! + 82!

Is it 6

Sorry. That's incorrect.
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###### CATOfficial Quant Thread for CAT 2011 [Part 3]
(x+y)=k(x-y)
=> (x+y)^2 = k(x-y)(x+y)
=> x^2+y^2+2xy = k(x^2-y^2)
=> x^2+y^2 = k(x^2-y^2)-2xy

Is it none of the above.

geometric approach :

(x+y) = k(x-y)

here, x+y is line 1 and x-y is line 2.
These who are equated hence they have same distance from the origion.

slope of line 1 : 1/1 = 1
slope of line 2 : -1/1 = -1

slope1*slope2 = -1
hence these two lines are perpendicular.

x^2+y^2 is the perpendicular distance from and of these two lines which is neither dependent om x^2-y^2 and xy.

so, Is it none of the above.
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