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@k_himanshu
96

meversusme SaysDefinately something wrong with the options : getting 400/9......

sorry for the misspelling of the options bro.

your answer is correct

The option was 44(4/9)

:D

- 1 Like

Yes, the options are correct. It is from Time Sectional test.

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@k_himanshu
96

Sachin, Saurav and Rahul enter into a partnership with capitals of 18000, 24000 and 48000. Saurav, apart from his share of profit, receives a certain percentage of the profit for managing the business. Sachin' s share in the profit is 30000. Find the percentage of the profit that Rahul receives if the total profit is 180000.

**a)** 444/9%

**b)** 361/3%

**c)** 531/3%

**d)** 345/9%

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@k_himanshu
96

Hey u all puys,plz solve this ques as it makes a lot of puzzle 2 me....

Q:-the no of terms in an AP is odd.if the sum of all terms is 45 and the no of terms is 4 more than tha middle term,find the middle term-

1.9

2.4

3.6

4.5

answer is 5

(n-1)*Middle Term = 45- Middle Term

so, Middle term = 45/n

now n=Middle term(m) +4

i.e. m(m+4) = 45

5(5+4) = 45

hence m = 5

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@k_himanshu
96

can you please tell what are the MBA programs that are available at Terry college of business?

Thanks in advance,

Himanshu

Is it 145 ?

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@k_himanshu
96

x - 7xy + 12y - 4 = 0

D should be a perfect sq

49y - 48y + 16 should be a perfect sq

y + 16 = p

(p - y)(p + y) = 16 = 2*8

p = 5, y = 3

So, only one possible value.

Hi chill Bhai,

I got your solution man however can you pls explain why D should have to be a perfect sq ?

Thanks,

Himanshu

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@k_himanshu
96

what is the last non zero digit for the sum

84! + 82!

Is it 6

Sorry. That's incorrect.

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@k_himanshu
96

(x+y)=k(x-y)

=> (x+y)^2 = k(x-y)(x+y)

=> x^2+y^2+2xy = k(x^2-y^2)

=> x^2+y^2 = k(x^2-y^2)-2xy

Is it none of the above.

geometric approach :

(x+y) = k(x-y)

here, x+y is line 1 and x-y is line 2.

These who are equated hence they have same distance from the origion.

slope of line 1 : 1/1 = 1

slope of line 2 : -1/1 = -1

slope1*slope2 = -1

hence these two lines are perpendicular.

x^2+y^2 is the perpendicular distance from and of these two lines which is neither dependent om x^2-y^2 and xy.

so, Is it none of the above.

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