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last two digits of 83^83^84^84 ?

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- @D.Uchiha using remainders is one way to go. OR.. you ca.... 12 Sep.
- so using remainders.. first find the last two digits of 8.... 12 Sep.

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@arvindpavithran
5

@D.Uchiha

using remainders is one way to go. OR.. you can use the eulers theorem ... to solve using remainders go thru this link ->

http://www.quantexpert.co.in/qenotes/quantnotes/numbers/44-secondlast-digit-of-any-power.html... for eulers..

http://www.princeton.edu/~achaney/tmve/wiki100k/docs/Euler_s_theorem.html...

@arvindpavithran
5

so using remainders.. first find the last two digits of 84^84 = (21*4)^84 --- last two digits =44 ... then 83^44 ... whose last two digits will be 21.. and finally 83^21 = 83^20*83..... 1*83 = 83

42 cubes of side 1cm are glued together to form a solid cuboid.if the perimeter of base of the cuboid is 18cm then find the number of possible heights (height being integer) ?

- 7Comments
- 3 cm!! (7,2) = 14 cubes per layer. 30 Aug.
- 1. 30 Aug.