jain4444

@jain4444

Highway66
Honky Tonk @Highway66
Aaj questions ka vrat h kya ! Post hi nai ho rahe ! :disappointed: Q). A sum of Rs 10 is lent to be returned in 11 monthly installments of Rs 1 each, interest being simple. The rate of interest is
jain4444
Abhishek Jain @jain4444

@Highway66 bhai @chillfactor sir ko tag toh kar dete...kya pata darshan dede

42 cubes of side 1cm are glued together to form a solid cuboid.if the perimeter of base of the cuboid is 18cm then find the number of possible heights (height being integer) ?

42 cubes of side 1cm are glued together to form a solid cuboid.if the perimeter of base of the cuboid is 18cm then find the number of possible heights (height being integer) ?

  • 7Comments
  • 3 cm!! (7,2) = 14 cubes per layer. 2d.
  • 1. 2d.
Highway66
Honky Tonk @Highway66
Aaj questions ka vrat h kya ! Post hi nai ho rahe ! :disappointed: Q). A sum of Rs 10 is lent to be returned in 11 monthly installments of Rs 1 each, interest being simple. The rate of interest is
jain4444
Abhishek Jain @jain4444

R/100(10+9+8+7+6+5+4+3+2+1) = 1

R = 12*(100/55) = 21.81 %

coolg
bm s @coolg
hi...can u plz rate time/ims/tathagat/mbaguru/cl in noida for cat14 coaching. m new to d place. plz suggest.
jain4444
Abhishek Jain @jain4444

go for alphanumeric.....they have online batches also  

girlfriday.ab
@girlfriday.ab
1)Sum of co primes to 840 and less than it? 2)Number of ways of expressing 11025 as a product of coprime factors?
jain4444
Abhishek Jain @jain4444

@aditya0788 it is okay for unordered but for ordered you have to count cases 

girlfriday.ab
@girlfriday.ab
1)Sum of co primes to 840 and less than it? 2)Number of ways of expressing 11025 as a product of coprime factors?
jain4444
Abhishek Jain @jain4444

assuming in 2nd question it is "product of 2 co-prime factors"

let 2 factors be X and Y

prime factorization of 11025 = 3^2 * 5^2 * 7^2 

now each power of prime number have 2 choices either X or Y

so , answer is 2^3 = 8 for unordered and 8/2 = 4 for ordered

sherlockk
G P @sherlockk
Akhil has a board, similar to chessboard, except that it has only 6x6 squares. He calculated the number of rectangles (including squares) on the board. How many distinct values can the area of these rectangles assume? a) 72 b) 24 c) 36 d) 54 e)18
jain4444
Abhishek Jain @jain4444

6*6 , 6*5 , .......... 1*1 = 21 

but 3 repetitions are there 

6*2 = 4*3 

3*2 = 6*1

4*1 = 2*2

so , 21 - 3 = 18

sherlockk
G P @sherlockk
In a box there are 90 slips, numbered from 1 to 90. Ramu picks up four slips at random, one after the other, without replacement. What is the probability that the numbers on the slips, in the order he picks them up, are in ascending order? a) 1/6 b) 1/12 c) 1/24 d) 2/45
jain4444
Abhishek Jain @jain4444

total cases = 4!

favorable cases = 1 

prob. 1/24

pokermaster
poker master @pokermaster
the difference between SI and CI for 3 years is at 5% is rs 122. Find the sum? Any shortcuts
jain4444
Abhishek Jain @jain4444

difference for 3 years = [pr^2(300 + r)]/100^3

preritnagori
PRERIT NAGORI @preritnagori
Can any1 suggest how is handa ka funda online prog for CAT14. also wheather it is advisible to join @ this hour?? pls tell how is handa ka funda mock?
jain4444
Abhishek Jain @jain4444

You can also try Alphanumeric Online courses