jain4444

@jain4444

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tinaxyz
taru gupta @tinaxyz
Hello...I want to join coaching institute for xat,snap,nmat and the upcoming exams in Delhi. I have given CAT this yr. Also i have heard time cp is good. Could you pls advice me which institute is best with less no of students in batch and best faculty. Also i had enrolled in time in bangalore.....
ShilpiNayar
Shilpi Nayar @ShilpiNayar
This is definitely off the track. Preparing for CAT 15. Currently working with Amazon. Unable to find time for regular coaching. Therefore have to rely solely on online coaching. Heard about CL Online Smart CAT cracker comprehensive but no substantial review is available. Any suggestions re...
jain4444
Study IQ @jain4444

You  Can Also try Alphanumeric Online course

harshcat91
HV S @harshcat91
"Link for Modern Maths Session : - we will discuss all questions from Permutation & Combination, Set Theory, etc. date : 20th Oct, Timings : 10 AM Onwards." https://alphanumeric-edu.webex.com/alphanumeric-edu/onstage/g.php?t=a&d;=669840931 *_Please register if you need revision in Modern Mat...
harshit961
Harshit Rastogi @harshit961
I want to join a coaching Institute in Delhi for CAT 15. I am confused between Tathagat/Alphanumeric/AnkGanit. Please suggest. Also what is the approx fee of all these institutes?
jain4444
Study IQ @jain4444

Alphanumeric  Fees is --- 50000

last two digits of 83^83^84^84 ?

  • 13 Comments
  • @D.Uchiha using remainders is one way to go. OR.. you ca.... 12 Sep.
  • so using remainders.. first find the last two digits of 8.... 12 Sep.
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arvindpavithran
KrackJack @arvindpavithran 27

so using remainders.. first find the last two digits of 84^84 = (21*4)^84 --- last two digits =44 ... then 83^44 ... whose last two digits will be 21.. and finally 83^21 = 83^20*83..... 1*83 = 83 

Highway66
Scooby Dooby Doooooo @Highway66
Aaj questions ka vrat h kya ! Post hi nai ho rahe ! :disappointed: Q). A sum of Rs 10 is lent to be returned in 11 monthly installments of Rs 1 each, interest being simple. The rate of interest is
jain4444
Study IQ @jain4444

@Highway66 bhai @chillfactor sir ko tag toh kar dete...kya pata darshan dede

42 cubes of side 1cm are glued together to form a solid cuboid.if the perimeter of base of the cuboid is 18cm then find the number of possible heights (height being integer) ?

  • 7 Comments
  • 3 cm!! (7,2) = 14 cubes per layer. 30 Aug.
  • 1. 30 Aug.
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Highway66
Scooby Dooby Doooooo @Highway66
Aaj questions ka vrat h kya ! Post hi nai ho rahe ! :disappointed: Q). A sum of Rs 10 is lent to be returned in 11 monthly installments of Rs 1 each, interest being simple. The rate of interest is
jain4444
Study IQ @jain4444

R/100(10+9+8+7+6+5+4+3+2+1) = 1

R = 12*(100/55) = 21.81 %

coolg
bm s @coolg
hi...can u plz rate time/ims/tathagat/mbaguru/cl in noida for cat14 coaching. m new to d place. plz suggest.
jain4444
Study IQ @jain4444

go for alphanumeric.....they have online batches also  

girlfriday.ab
@girlfriday.ab
1)Sum of co primes to 840 and less than it? 2)Number of ways of expressing 11025 as a product of coprime factors?
jain4444
Study IQ @jain4444

@aditya0788 it is okay for unordered but for ordered you have to count cases