Posts and Comments

@enigma2011
48

> If a and b are roots, then
ab = 1/(I - m) = 2a^2
a + b = I/(m - I) = 3a
=> 2I^2/9(I - m)^2 = 1/(I - m)
=> *2I^2 - 9I + 9m = 0
=> 81 - 72m 0*
=> m 9/8
Chill bhai can you please xplain the part in Bold., Are I & M simple variables?

If a and b are roots, then

ab = 1/(I - m) = 2a^2

a + b = I/(m - I) = 3a

=> 2I^2/9(I - m)^2 = 1/(I - m)

=>2I^2 - 9I + 9m = 0

=> 81 - 72m 0

=> m 9/8

Chill bhai can you please xplain the part in Bold., Are I & M simple variables?

@enigma2011
48

> Ohh and help for this question as well
Q.In a packing unit of a chemical factory,one machine fills the bottles at rate of 25 bottles per min & needs to be switched off for 10 mins after filling every 500 bottels.Another machine can seal the filled bottles at the rate of *400 *bottles per m...

Ohh and help for this question as well

Q.In a packing unit of a chemical factory,one machine fills the bottles at rate of 25 bottles per min & needs to be switched off for 10 mins after filling every 500 bottels.Another machine can seal the filled bottles at the rate of400bottles per min & needs to be switched off for 5 mins after every 400 bottles. If both the machines start at the same time, that is 8 am, find the earliest time at which 4000 packed & sealed bottles will be ready for delivery?

a)12:10

b)12 noon

c)12:05

d)11:50

(I got 12:10 but the correct answer is 12:05)

Hey one doubt, do the sealing rate is 400 bottles per minutes? I m getting none of these:shock:

@enigma2011
48

> Xane Says
>
> 7^3 = 343... so 3 must be te 12th digit from left.. or 1st from right..
Hey Jainbhai and Xane.. dint understand how its 3. whats the catch here?:banghead:

Xane Says7^3 = 343... so 3 must be te 12th digit from left.. or 1st from right..

Hey Jainbhai and Xane.. dint understand how its 3. whats the catch here?:banghead:

@enigma2011
48

1..The number of quadratic eqns which are unchanged by squaring their roots =
a..2 b..4 c..6 d..none of these
Plz post the approach too ::

1..The number of quadratic eqns which are unchanged by squaring their roots =

a..2 b..4 c..6 d..none of these

Plz post the approach too

a..2 b..4 c..6 d..none of these

Plz post the approach too

@enigma2011
48

hey puys.. CAT Registration has just begun . Please post your dates and location!! The Countdown begins.. ATB!!!! :: ::

hey puys.. CAT Registration has just begun . Please post your dates and location!! The Countdown begins.. ATB!!!!

- 8 Likes

@enigma2011
48

> gs4890 Says
>
> answer has to be cbd. there are so many possibilities bhai and how did u come out to know that rohan's current age is 14.
same doubt.. Puys how can we be sure that his age is 14? Did i miss out on any part of the question?

gs4890 Saysanswer has to be cbd. there are so many possibilities bhai and how did u come out to know that rohan's current age is 14.

same doubt.. Puys how can we be sure that his age is 14? Did i miss out on any part of the question?

@enigma2011
48

> Draw venn diagram and check for people who are reading BT+BI. these are 12. we remove them and move them to BI+BW category.
remaining will come from BT ONLY category.
total people not reading BI or BW = 300 - (207 +4) = 99
not in options. Not sure what went wrong.
Can anyone check...

Draw venn diagram and check for people who are reading BT+BI. these are 12. we remove them and move them to BI+BW category.

remaining will come from BT ONLY category.

total people not reading BI or BW = 300 - (207 +4) = 99

not in options. Not sure what went wrong.

Can anyone check?

Is the Venn correct.. I guess the question should be how many read BI & BW

@enigma2011
48

> A survey of 300 respondents showed that 135 of them read Business India ,125 read Business Today and 115 read Business World .Further ,42 of the respondents read Business India and Business Today,48 read Business Today and Business World ,43 read Business India and Business World and 30 of the ...

A survey of 300 respondents showed that 135 of them read Business India ,125 read Business Today and 115 read Business World .Further ,42 of the respondents read Business India and Business Today,48 read Business Today and Business World ,43 read Business India and Business World and 30 of the respondents read all the three magazines

Q2) If 16 of the respondents who were reading Business Today ,stop reading Business Today and instead start reading Business world , then what is the maximum number of respondentswho will notbe reading Business India and Business World

(1) 59

(2)55

(3)75

(4) 63

plzz postr the approach as well

Are you sure its 'who will not"? I getting a answer of 59 if the question is "who will be"..

@enigma2011
48

> Krazy_me Says
>
> Bhai, can you please explain the bold part? Didn't get! ::
Arithmetic mean > Geometric Mean..
As x,y,z are in AP y=(x+z)/2
three numbers : AM=(x+y+z)/3....(i)
GM= (xyz)^1/3 .....(ii)
substitute x+z=2y in (i) and xyz=4 in (ii).
We get 3y/3 > 4...

Krazy_me SaysBhai, can you please explain the bold part? Didn't get!

Arithmetic mean > Geometric Mean..

As x,y,z are in AP y=(x+z)/2

three numbers : AM=(x+y+z)/3....(i)

GM= (xyz)^1/3 .....(ii)

substitute x+z=2y in (i) and xyz=4 in (ii).

We get 3y/3 > 4 ^(1/3)

Hope its clear..

P.S : There are my first few quant posts. Please bear with me puys..

- 6 Likes

@enigma2011
48

> puys pls solve this sum..
m not getting it ::
given xyz = 4 and xyz are in AP.. As xyz are in AP and so 2y= x+z ..
For any series we know AM>=GM..
Hence (x+y+z)/3 >= (xyz)^1/3
3y/3>4^(1/3)
y>= 2^(2/3)..
Whats the OA? ::

puys pls solve this sum..

m not getting it

given xyz = 4 and xyz are in AP.. As xyz are in AP and so 2y= x+z ..

For any series we know AM>=GM..

Hence (x+y+z)/3 >= (xyz)^1/3

3y/3>4^(1/3)

y>= 2^(2/3)..

Whats the OA?

- 4 Likes

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