one q/s which i am nt able to solve.....
We are selecting a group of 10 numbers out a list of 100 odd numbers. The sum is called A. How many different values of A are possible....
Reminder I dont have the answer.. Just saw this q/s in some QA Notes.... Please tell if anyone knows the method( i know here i will find the answer)
consider the first 100 odd numbers: 1,3,5....199
The sum of first 10 odd numbers( i.e 1+3+5....19) = 10 + 45x2 = 100 ( min value)
The sum of last 10 odd nos ( i.e 181 + 183...199) = 10 + 945x2 = 1900( max value)
now any other value of the sum will lie betwn 100 and 1900 at a difference of 2.
so total values = (1900-100)/2 + 1
900 + 1 = 901.