atul7

@atul7

  • A P Gupta
  • 11 karma
ObLiViOn 
sushanthabc
Isolated Soul @sushanthabc
Raju has 128 boxes with him. He has to put at least 120 oranges in one box and 144 at the most. Then the least number of boxes which will have the same number of oranges is:
sushanthabc
Isolated Soul @sushanthabc
Raju has 128 boxes with him. He has to put at least 120 oranges in one box and 144 at the most. Then the least number of boxes which will have the same number of oranges is:
atul7
A P Gupta @atul7

@Highway66 @sushanthabc ,what is the issue with 5 , it is the least number of box with same no of orange ?? 

vivekhooda
Leonard . @vivekhooda
Value of n for the Highest term of the sequence where n is integer n^10/2^n
atul7
A P Gupta @atul7

@Highway66 agree with you on this , i wonder if cat will ever test on these questions given what came in 2014

vivekhooda
Leonard . @vivekhooda
Value of n for the Highest term of the sequence where n is integer n^10/2^n
atul7
A P Gupta @atul7

@Highway66 i meant the question asks only for integral values , i am assuming it to be a continuos function and saying for other integral values greater than 14 the functions value decreases , so maxima occurs at 14 , sorry for the garbled line

daniellafonseca
danygirl @daniellafonseca
b) Find a30 given that the first few terms of an arithmetic sequence are given by 6,12,18,... guys for this problem is it right to put a30 instead of tn where tn=a+(n-1)d
vivekhooda
Leonard . @vivekhooda
Value of n for the Highest term of the sequence where n is integer n^10/2^n
atul7
A P Gupta @atul7

assume the function to be x^10/2^x ; derivative nikal kar you get 

(2^x*10x^9-x^10*2^xln2)/(denominator) = 0 ;

x = 14.426 , so at 15 the function decreases hence maximum at 14 given that fuction takes integral values

google "graph x^10/2^x" , it will give an idea

daniellafonseca
danygirl @daniellafonseca
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there? A. 159 B. 209 C. 201D. 212 approach ?
atul7
A P Gupta @atul7

You get the value from taking cases of selecting 4 children and subracting cases with no boys 

so , selecting 4 children = 10C4 ; Case where no boys are selected = 4C4 = 1

Required Ways = 10C4-4C4 = 209 

sushanthabc
Isolated Soul @sushanthabc
If ax2 \- bx + 5 = 0 does not have 2 distinct real roots, then find the minimum value of 5a + b
atul7
A P Gupta @atul7

b^2-20a

given to find minimum value of 5a+b

so , a>=b^2/20 , 5a+b >= 5*b^2/20 +b , 5a+b >= b^2/4 + b 

5a+b >= (b/2 +1 )^2 - 1 ; hence the min value is -1 at b=-2 

ak9478
ak 9478 @ak9478
Yana and Gupta leave points x and y towards y and x respectively simultaneously and travel in the same route. After meeting each other on the way, Yana takes 4 hours to reach her destination, while Gupta takes 9 hours to reach his destination. If the speed of Yana is 48 km/hr, what is the speed o...
vivekhooda
Leonard . @vivekhooda
How many pairs of consecutive numbers between (1000)base9 to (2000)base 9 can a person add such that there is no carry over from one column to the next
atul7
A P Gupta @atul7

1004-1005 ,

1088 1188 1288 1388 , doesn't these additions have carry overs ?