Posts and Comments

@ank707
95

Posted 15 Mar '12

Im living near Marathalii and preparing too.....
What material are u referring to ?

Im living near Marathalii and preparing too.....

What material are u referring to ?

What material are u referring to ?

@ank707
95

Posted 01 Oct '11

@ seniors....
kindly guide me if my profile is gud enuf for the GMP program...im thinking about taking XAT-12 to apply for this program....
Xth: 79.4% CBSE
12th: 74.4 % CBSE
BE: 68.62 % in Elex and Comm
work profile: 4+ yrs of experience in Telecom domain. Working with telecom ...

@ seniors....

kindly guide me if my profile is gud enuf for the GMP program...im thinking about taking XAT-12 to apply for this program....

Xth: 79.4% CBSE

12th: 74.4 % CBSE

BE: 68.62 % in Elex and Comm

work profile: 4+ yrs of experience in Telecom domain. Working with telecom giant Nokia-Siemens Networks as RF planning and optimisation engg. No managerial exp but have a team of 4 engg under me. Have performed planning and optimisation for existing GSM and 3G netwroks. Was involved in various parameters and features testing all these years on 2G and 3G networks.No intl exp. only thing that i feel makes me my profile differ from other is my professional background as i think crowd is more from IT domain. EC revolves around sports activities including heading Football team at school level

current exp is 4.4 yrs and by mar-12 it will be 4 yr 10 mnths....so is there chance of relaxation on this part..??

kindly guide me if my profile is gud enuf for the GMP program...im thinking about taking XAT-12 to apply for this program....

Xth: 79.4% CBSE

12th: 74.4 % CBSE

BE: 68.62 % in Elex and Comm

work profile: 4+ yrs of experience in Telecom domain. Working with telecom giant Nokia-Siemens Networks as RF planning and optimisation engg. No managerial exp but have a team of 4 engg under me. Have performed planning and optimisation for existing GSM and 3G netwroks. Was involved in various parameters and features testing all these years on 2G and 3G networks.No intl exp. only thing that i feel makes me my profile differ from other is my professional background as i think crowd is more from IT domain. EC revolves around sports activities including heading Football team at school level

current exp is 4.4 yrs and by mar-12 it will be 4 yr 10 mnths....so is there chance of relaxation on this part..??

@ank707
95

Posted 25 Aug '11

if a:b=5:4 , b:c=7:3 and c:d=5:2 then how can we write this in continuous ratio form...i.e a:b:c:d...??

if a:b=5:4 , b:c=7:3 and c:d=5:2 then how can we write this in continuous ratio form...i.e a:b:c:d...??

@ank707
95

Posted 12 Jul '11

any shortcut for finding higher powers of a decimal no. say (1.07)^7 or (1.59)^11 ...
my apologies if this is a re-post bt i did searched n cudnt find the answ...

any shortcut for finding higher powers of a decimal no. say (1.07)^7 or (1.59)^11 ...

my apologies if this is a re-post bt i did searched n cudnt find the answ...

my apologies if this is a re-post bt i did searched n cudnt find the answ...

@ank707
95

Posted 10 Jul '11

> Take 4 parts of 2nd and 1 part of 1st hence we have to make it 35ltrs
I.e. 24Ltrs of 2nd and 11ltrs of 1st
y 4 parts from 2nd vessel....cud u plz elaborate a lil...im very poor wen it cms to meixtures... ::

Take 4 parts of 2nd and 1 part of 1st hence we have to make it 35ltrs

I.e. 24Ltrs of 2nd and 11ltrs of 1st

y 4 parts from 2nd vessel....cud u plz elaborate a lil...im very poor wen it cms to meixtures...

jain4444 SaysIs It 11 ?

yes....appproach plz...

@ank707
95

Posted 10 Jul '11

Two vessels contain mixtures of spirit and water. In the first vessel the ratio of spirit to water is 8 : 3 and in the second the ratio is 5 : 1. A 35-litre cask is filled from these vessels so as to contain a mixture of spirit and water in the ratio of 4 : 1. How many litres are taken from the f...

Two vessels contain mixtures of spirit and water. In the first vessel the ratio of spirit to water is 8 : 3 and in the second the ratio is 5 : 1. A 35-litre cask is filled from these vessels so as to contain a mixture of spirit and water in the ratio of 4 : 1. How many litres are taken from the first vessel?

@ank707
95

Posted 08 Jul '11

> last non zero digit of 96!
plz xplain d method for these kinda ques(i.e. when the no. is not a multiple of 10)
Originally Posted by amitkrsingh
Puys,
Find last non zero digit of 80! and 76!
To find out the last non zero digit of n!
Z(n)-> denotes the last non zero digit ...

last non zero digit of 96!

plz xplain d method for these kinda ques(i.e. when the no. is not a multiple of 10)

Originally Posted by amitkrsingh

Puys,

Find last non zero digit of 80! and 76!

To find out the last non zero digit of n!

Z(n)-> denotes the last non zero digit in expansion of n factorial

L(n)-> denotes the last digit(unit digit) of n.

Z(n)=L(4^(number of tens in n)) * Z() * Z(n%10)

[]- is the Greatest integer function.

Note:-no of tens means the quotient obtained on dividing the number by 10

So Z(80) = L(4^8 ) * Z(16) * Z(0)

Z(16) = L * Z(3) * Z(6) = 4*6*2 = 8

Z(80) = 6*8 = 8

To Calculate z(76) -

then Z(76)*7*8*9*8 = 8 (Its multiplication of all the last non zero digit of 76!,77,78,79,80)

76!*2 = 8

so last non-zero digit of 76! = 4

@ank707
95

Posted 08 Jul '11

Originally Posted by amitkrsingh
Puys,
Find last non zero digit of 80! and 76!
To find out the last non zero digit of n!
Z(n)-> denotes the last non zero digit in expansion of n factorial
L(n)-> denotes the last digit(unit digit) of n.
Z(n)=L(4^(number of tens in n)) * Z() * Z(...

Originally Posted by amitkrsingh

Puys,

Find last non zero digit of 80! and 76!

To find out the last non zero digit of n!

Z(n)-> denotes the last non zero digit in expansion of n factorial

L(n)-> denotes the last digit(unit digit) of n.

Z(n)=L(4^(number of tens in n)) * Z() * Z(n%10)

[]- is the Greatest integer function.

Note:-no of tens means the quotient obtained on dividing the number by 10

So Z(80) = L(4^8 ) * Z(16) * Z(0)

Z(16) = L * Z(3) * Z(6) = 4*6*2 = 8

Z(80) = 6*8 = 8

To Calculate z(76) -

then Z(76)*7*8*9*8 = 8 (Its multiplication of all the last non zero digit of 76!,77,78,79,80)

76!*2 = 8

so last non-zero digit of 76! = 4

Puys,

Find last non zero digit of 80! and 76!

To find out the last non zero digit of n!

Z(n)-> denotes the last non zero digit in expansion of n factorial

L(n)-> denotes the last digit(unit digit) of n.

Z(n)=L(4^(number of tens in n)) * Z() * Z(n%10)

[]- is the Greatest integer function.

Note:-no of tens means the quotient obtained on dividing the number by 10

So Z(80) = L(4^8 ) * Z(16) * Z(0)

Z(16) = L * Z(3) * Z(6) = 4*6*2 = 8

Z(80) = 6*8 = 8

To Calculate z(76) -

then Z(76)*7*8*9*8 = 8 (Its multiplication of all the last non zero digit of 76!,77,78,79,80)

76!*2 = 8

so last non-zero digit of 76! = 4

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