answers in bold??
@ninad bhai kuch missing lagta hai??
i have a method.....
consider the speed of A be 3x and that of B be x.
time at which they meet for the first time will be = distance/relative speed.
relative speed = 3x+x(opposite direction in circular tracks)=4x
distance =2pie r=2*22/7*7=44km
so they will meet after =44/4x=11/s minutes
distance travelled by A will be 3x*11/x=33km and by b will be 11 km at M1
so their next meeting will be after 22km from m0 and 11km from M1
1)11 km ---ans
2) i din get the question
3) each time they meet in a differnce of 11km so their fourth meeting will be after 44km from starting point...M4
4)firstly A travels with a speed of 3x....ie 3x*11/s=33km....then it will travel again with a speed of x km/hr= x*11/x=11Km.....again it will travel with 3x speed so 33 km