akhilkjoseph

@akhilkjoseph

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akhilkjoseph
akhil joseph @akhilkjoseph
Guys i just want to know, how many marks is needed as per you to score minimum 95% in this cat, or how many questions need to be right in order to achieve this.
akhilkjoseph
akhil joseph @akhilkjoseph

vikas..... i just want to get an overview...thats all

akhilkjoseph
akhil joseph @akhilkjoseph
Guys i just want to know, how many marks is needed as per you to score minimum 95% in this cat, or how many questions need to be right in order to achieve this.
akhilkjoseph
akhil joseph @akhilkjoseph

you mean 110 marks, how many mrk for each ques, do you have any idea about sessional cut offs

Guys i just want to know, how many marks is needed as per you to score minimum 95% in this cat, or how many questions need to be right in order to achieve this.

  • 4Comments
  • you mean 110 marks, how many mrk for each ques, do you ha.... 09 Oct.
  • vikas..... i just want to get an overview...thats all. 09 Oct.
vikcat
red skull sharma @vikcat 129

bhai pattern change ho gya hai so no one can predict anything ...but 25 25 will certainly fetch u a good score..!

akhilkjoseph
akhil joseph @akhilkjoseph

you mean 110 marks, how many mrk for each ques, do you have any idea about sessional cut offs

akhilkjoseph
akhil joseph @akhilkjoseph

vikas..... i just want to get an overview...thats all

neels11
Neela Kandan @neels11
If anyone needs Byju's "Final lap for CAT" ( 2011 ) Quant and LR-DI Handouts, PM me ur mail id, I have the scanned copy. Don't ask me for the classwork notes 'coz its hard for you to get anything out of my classwork notes! :: Please note that Byju sir didn't give any materials other than the ha...
If 10^x is divided by 13 and remainder is 1....
we know a^(p-1)/p remainder is 1 if a and p are relatively prime --- this is a property, i dont know the name...
therefore for x= 12, the equality would hold, similarly for 10^24..it would hold again as (10^12)^2 == (mod1)^2....
therefore net anser would be 100/12 == 8 values


Some correction

also check for 10^6/13 which would make all multiples of 6 as the answer, hence net answer would be 8*2 =16





i got the answer as 16.
yeah its 12

mn bhai mei apne kamjoor student ka hath beech mein nahi chodta :cheerio::cheerio::cheerio::cheerio:




i also got it as 12..
1 - If the roots of the equation (a^2 + b^2)x^2 - 2(ac+bd)x + (c^2 + d^2) = 0 are equal then which of the following is true?
1 - ab = cd
2 - ad = bc
3 - ad = bc^1/2( square root of bc)
4 - ab = cd^1/2( square root of cd)
5 - abc = d^1/2( square root of d)

2 - Find the value of the expression
(sqrt x +( sqrt x+ ( sqrt x... +)))

3 - Find the maximum value of the function 1/ ( x^2 - 3x + 2)
a - 11/4
b - 1/4
c - 0
d - -4
e - none of these

( guys plz tell me the approach to sovling such sums - max and min value types)

4 - Find the minimu m v alue of the function
f(x) = log (x^2 - 2x + 5 ) to the base 2 .
a - -4
b - 2
c - 4
d - -2
e - negative infinity


these are my answers.....
)ad=bc
2)2sqrt(x)
3)-4
4)-4


these are my answers.....:splat::splat::splat:

1)ad=bc
2)2sqrt(x)
3)-4
4)-4
answers in bold??

@ninad bhai kuch missing lagta hai??



i have a method.....
consider the speed of A be 3x and that of B be x.

time at which they meet for the first time will be = distance/relative speed.

relative speed = 3x+x(opposite direction in circular tracks)=4x

distance =2pie r=2*22/7*7=44km

so they will meet after =44/4x=11/s minutes

distance travelled by A will be 3x*11/x=33km and by b will be 11 km at M1

so their next meeting will be after 22km from m0 and 11km from M1
1)11 km ---ans

2) i din get the question

3) each time they meet in a differnce of 11km so their fourth meeting will be after 44km from starting point...M4

4)firstly A travels with a speed of 3x....ie 3x*11/s=33km....then it will travel again with a speed of x km/hr= x*11/x=11Km.....again it will travel with 3x speed so 33 km

total=33+33+11=77.
i have a method.....
consider the speed of A be 3x and that of B be x.

time at which they meet for the first time will be = distance/relative speed.

relative speed = 3x+x(opposite direction in circular tracks)=4x

distance =2pie r=2*22/7*7=44km

so they will meet after =44/4x=11/s minutes

distance travelled by A will be 3x*11/x=33km and by b will be 11 km at M1

so their next meeting will be after 22km from m0 and 11km from M1
1)11 km ---ans

2) i din get the question

3) each time they meet in a differnce of 11km so their fourth meeting will be after 44km from starting point...M4

4)firstly A travels with a speed of 3x....ie 3x*11/s=33km....then it will travel again with a speed of x km/hr= x*11/x=11Km.....again it will travel with 3x speed so 33 km

total=33+33+11=77.