# @airirm

##### Sundar :) 151 karma
###### CATOfficial Quant Thread for CAT 2014!!
Sundar :) @airirm
Sundar :) @airirm
@clxlfms Ji please share the explanation..
###### CATOfficial Quant Thread for CAT 2014!!
Sundar :) @airirm
Sundar :) @airirm
@clxlfms This is the complete question ji. Is there any way of solving this?
###### CATOfficial Quant thread for CAT 2013

• 2 Likes
• Let total combined income be I and total combined tax be .... 06 Apr.
• What was the question no 11 ??. 05 Apr.
##### Attachments
shashank saxena @shasha271189 4
Let total combined income be I and total combined tax be T. just assume that A will pay 10 % tax and B 20% tax. Note that to calculate the tax of B, 10% will be on 2,00,000 and 20 % on rest income. Just take the ration of taxes of A and B (both in terms of I) and equate it to 1/2 (as evident from the tax pie chart).
Joydeep Debnath @joy161989 83
What was the question no 11 ??
###### CATOfficial Quant Thread for CAT 2014!!

• 1) 18/26 ?. 05 Apr.
• @clxlfms This is the complete question ji. Is there any w.... 05 Apr.
##### Attachments
A K @clxlfms 477
13) 14 lakhs ??
A K @clxlfms 477
@airirm let total income be I= Ia+ Ib+ Ic+ Id where ia,b,c,d are incomes of A,BC,D respectively.
Now, TOtal income can also be written as I= 3(Ia+Ib) but I= (100/13.33)*Ia hence => Ia=(2/3)*Ib-----1)
similarly, TOTAL tax=T= 4(Ta+Tb) but T=(100/8.33)*Ta => Tb~ 2 Ta ----------2)
solving them we get Ia post tax/ Ib post tax= 9/13= 18/26
Ps- Some approximations i have taken.
Sundar :) @airirm 151
@clxlfms Ji please share the explanation..
Sundar :) @airirm 151
@clxlfms This is the complete question ji. Is there any way of solving this?
###### CAT[Official] LR-DI Thread for CAT 2014

• data missign. 07 May.
• @airirm it seems some data is missing... all values are i.... 11 Apr.
##### Attachments
Vaibhav Gupta @pheonix2013 759
@airirm it seems some data is missing... all values are in %ges ..how can u find absolute value for any quantity ?
###### CATOfficial Quant Thread for CAT 2014!!
Sundar :) @airirm
Escalators _/\\_ (Q1) P and Q walk up a moving up escalator at constant speeds. For every 5 steps that P takes Q takes 3 steps. How many steps would each have to climb when the escalator is switched off, given that P takes 50 and Q takes 40 steps to climb up the moving up escalator respecti...
Sundar :) @airirm
@garry1337 Thanks a lot for the explanation and the link. I'm reading the article right away! Thanks again
###### CATOfficial Quant Thread for CAT 2014!!
Sundar :) @airirm
Escalators _/\\_ (Q1) P and Q walk up a moving up escalator at constant speeds. For every 5 steps that P takes Q takes 3 steps. How many steps would each have to climb when the escalator is switched off, given that P takes 50 and Q takes 40 steps to climb up the moving up escalator respecti...
Sundar :) @airirm
###### CATOfficial Quant Thread for CAT 2014!!

Escalators _/\_

(Q1) P and Q walk up a moving up escalator at constant speeds. For every 5 steps that P takes Q takes 3 steps. How many steps would each have to climb when the escalator is switched off, given that P takes 50 and Q takes 40 steps to climb up the moving up escalator respectively?

(1) 80 (2) 90(3) 100 (4) None of these

(Q2) A can take 10 steps per second and B can take 7 steps per second. A mischievously starts climbing down an escalator that is moving upwards and at the same instant B starts climbing up the same escalator. They meet after 5 seconds. If the escalator works at a steady rate of 4 steps per second then how many steps are visible when the escalator is stopped?

(1) 90 (2) 80(3) 85 (4) None of these

(Q3) In the above question, if the escalator was shut off at the instant when A and B meet,both being on different steps with A located above B, then how many steps from the ground is the step on which B stands?

(1) 45 (2) 65(3) 75 (4) 55

• @garry1337 Ji please share your approach... 26 Feb.
• @airirm Q1) 80 Q2) 85 Q3) 55 Will share the appr.... 26 Feb.
Badri @garry1337 1.7 k
@airirm
1) Speed of P = 5v Q=3v Escalator =e
Total steps in escalator = Steps covered by P + Steps covered by escalator in that time

Total steps in escalator = Steps covered by Q + Steps covered by escalator in that time

50 + e*(50/5v) = 40 + e*(40/3v) ------------------ (1)
e/v = 3
Substitute this back in equation 1
50 + 30 =80 steps

2) A = 10 ; B = 7 ; E = 4
Total steps = 5*(10-4) + 5*(7+4) = 85 steps

3) In 5 sec B would be at 5*(7+4) = 55th step
Mr Anderson @Master-Yoda 626
Q1)
50=5x/(5+v)
40=3x/(3+v)
where x is total step and v is esc speed
Q2) (10-v+7+v)*5
Q3)(7+4)*5=55
Sundar :) @airirm 151
Badri @garry1337 1.7 k
@airirm
Q1) 80
Q2) 85
Q3) 55
Will share the approach if the answers are correct.
###### CATOfficial Quant thread for CAT 2013

Escalators _/\_

(Q1) P and Q walk up a moving up escalator at constant speeds. For every 5 steps that P takes Q takes 3 steps. How many steps would each have to climb when the escalator is switched off, given that P takes 50 and Q takes 40 steps to climb up the moving up escalator respectively?

(1) 80 (2) 90(3) 100 (4) None of these

(Q2) A can take 10 steps per second and B can take 7 steps per second. A mischievously starts climbing down an escalator that is moving upwards and at the same instant B starts climbing up the same escalator. They meet after 5 seconds. If the escalator works at a steady rate of 4 steps per second then how many steps are visible when the escalator is stopped?

(1) 90 (2) 80(3) 85 (4) None of these

(Q3) In the above question, if the escalator was shut off at the instant when A and B meet,both being on different steps with A located above B, then how many steps from the ground is the step on which B stands?

(1) 45 (2) 65(3) 75 (4) 55

• 1 Like   6Comments
• Q3. (4)55. 27 Feb.
• Q2. (3)85. 27 Feb.
Swapnil Jha @swapnil4ever2u 1.8 k
Q2) 10*5 - 5*4 + 7*5 + 5*4 = 85 steps
Swapnil Jha @swapnil4ever2u 1.8 k
Q1) let the speed of steps be x steps/sec
50+ 10x = 40 + (40/3)x
=> x = 3 steps/sec
therefore total steps = 50 + 10*3 = 80 steps
###### CATQuant by Arun Sharma

Escalators _/\_

(Q1) P and Q walk up a moving up escalator at constant speeds. For every 5 steps that P takes Q takes 3 steps. How many steps would each have to climb when the escalator is switched off, given that P takes 50 and Q takes 40 steps to climb up the moving up escalator respectively?

(1) 80 (2) 90(3) 100 (4) None of these

(Q2) A can take 10 steps per second and B can take 7 steps per second. A mischievously starts climbing down an escalator that is moving upwards and at the same instant B starts climbing up the same escalator. They meet after 5 seconds. If the escalator works at a steady rate of 4 steps per second then how many steps are visible when the escalator is stopped?

(1) 90 (2) 80(3) 85 (4) None of these

(Q3) In the above question, if the escalator was shut off at the instant when A and B meet,both being on different steps with A located above B, then how many steps from the ground is the step on which B stands?

(1) 45 (2) 65(3) 75 (4) 55