Find 3d + 2e, where a, b, c, d, e satisfies:-
2a + b + c + d + e = 6
a + 2b + c + d + e = 12
a + b + 2c + d + e = 24
a + b + c + 2d + e = 48
a + b + c + d + 2e = 96
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@ Amit sir
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How many 3 digit numbers exist such that
a) When divided by 11 or 12 they leave a remainder of 7 and 8 respectively
b) When divided by 33 or 24 they leave a remainder of 29 and 20 respectively
c) When divided by 7 or 8 they leave a remainder of 4 in each case